A fast food restaurant has one drive through window. An average of 40 customer per-hour arrive at the window. It takes an averag
e of 1 minute to serve a customer. Assume that inter-arrival and service times are exponential.
a On the average, how many customers are waiting in line?
b On the average, how long does a customer spend at the restaurant (from time of arrival to time service is completed)?
c What fraction of the time are more than 3 cars waiting for service (this includes the car (if any) at the window)?
a On the average, how many customers are waiting in line?
b On the average, how long does a customer spend at the restaurant (from time of arrival to time service is completed)?
c What fraction of the time are more than 3 cars waiting for service (this includes the car (if any) at the window)?
1 answer:
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Given:
5 pounds = 2.268 kilograms
To find:
The number of kilograms in 2 pounds.
Solution:
We have,
5 pounds = 2.268 kilograms
Divide both sides by 5.
1 pounds = kilograms
1 pounds = 0.4536 kilograms
Multiply both sides by 2.
2 pounds = 2×0.4536 kilograms
2 pounds = 0.9072 kilograms
Therefore, the correct option is B.