Answer and Explanation:
Given : The random variable x has the following probability distribution.
To find :
a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.
b. Calculate the expected value of x.
c. Calculate the variance of x.
d. Calculate the standard deviation of x.
Solution :
First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.25 0 0 0
1 0.20 0.20 1 0.20
2 0.15 0.3 4 0.6
3 0.30 0.9 9 2.7
4 0.10 0.4 16 1.6
∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1
a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.


Yes it is a probability distribution.
b) The expected value of x is defined as

c) The variance of x is defined as

d) The standard deviation of x is defined as



By definition the area of a rectangle is:
A = l * w
Where,
l: long
w: width
So we have to clear the width:
w = A / l
Substituting the values:
w = (234) / (18) = 13
w = 13 feets
answer
the width, in feet, of the room is 13
1. (0.5)2=1
2. (-0.2) + (-0.05) = -0.25
3. |-3 + 2.75| = 0.25
4. -(-0.25) = 0.25
5. 2x - 1.75x = 0.25x
So your answers are 3 and 4.
<span> 3 x (4 + 5) as (3 x 4) + (3 x 5)
This is the distributive property</span>
I think it is 22, but I did it in my head so i might be way off
What you do is you “take apart” the net so it has individual rectangles, then you multiply the 2 sides... you do that for each rectangle then add it all up