Ask question

Ask question

All categories

3 years ago

15

Given a dilation around the origin, what is the scale factor K?

1 answer:

kobusy [5.1K]3 years ago

5 0

Answer:

The answer is " $\frac{4}{3}$ "

Step-by-step explanation:

Given:

$\bold{DoK = (12, 8) (9,6)}$

In the scale factor when we take x coordinate then the value of k is:

$\Rightarrow x= \frac{x_1}{x_2}\\\\\Rightarrow x= \frac{12}{9}\\\\\Rightarrow x= \frac{4}{3}\\$

If we take y coordinate then the value of k is:

$\Rightarrow y= \frac{y_1}{y_2}\\\\\Rightarrow y= \frac{8}{6}\\\\\Rightarrow y= \frac{4}{3}\\$

So, the final value of k is " $\frac{4}{3}$ " .

You might be interested in

33 47 51 53 59 59 83 99 what is the middle

Jobisdone [24]

Answer:

59

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

the volume V of a gas at a constant temperature varies inversely with the pressure P. when the volume is 100 cubic inches the pr

fiasKO [112]

Answer:

The pressure is $20\ psi$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

In this problem we have

$V*P=k$

where

V is the volume of a gas at a constant temperature

P is the pressure

we have

For $V=100\ in^{3}$ , $P=25\ psi$

step 1

Find the value of k

substitute the values of V and P

$100*25=k$

$k=2,500$

The equation is equal to $V*P=2,500$

step 2

Find the pressure when the volume is 125 cubic inches

For $V=125\ in^{3}$

substitute in the equation and solve for P

$125*P=2,500$

$P=2,500/125=20\ psi$

8 0

3 years ago

What is the sign of 3 x y 3xy3, x, y when x > 0 x>0x, is greater than, 0 and y < 0 y<0

Colt1911 [192]

Answer:

The sign is negative

Step-by-step explanation:

Given

$Expression = 3xy$

$x > 0$

$y$

Required

Determine the sign

The expression can be split into 3 factors

$(3) (x) (y)$

If x > 0 then x is positive and If y < 0 then y is negative

So, the expression becomes:

$(+3) (+x) (-y)$

<em />

Leave only signs

$(+) (+) (-)$

$+ * + = -$

So, we have:

$(+*+) (-)$

$(+) (-)$

$+ * - = -$

So, we have:

$(+) (-) = -$

<em>Hence, the sign of the expression is negative</em>

<em></em>

Take for instance;

$x = 2$

$y = -4$

The expression would be:

$3 *2 * - 4 =-24$ -- negative

4 0

3 years ago

I will mark you brainliest just give me the answer please. (I suck at math a lot.) 2s + 7 < 13: 1, 2, 3

AleksandrR [38]

Answer:

3

Step-by-step explanation:

mark brainliest

4 0

2 years ago

Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com

fredd [130]

$f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}$

$f$ has critical points where the derivative is 0:

$2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1$

The second derivative is

$f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}$

and $f''(-1)=\frac2e>0$ , which indicates a local minimum at $x=-1$ with a value of $f(-1)=\frac1e$ .

At the endpoints of [-2, 2], we have $f(-2)=1$ and $f(2)=e^8$ , so that $f$ has an absolute minimum of $\frac1e$ and an absolute maximum of $e^8$ on [-2, 2].

So we have

$\dfrac1e\le f(x)\le e^8$

$\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx$

$\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}$

5 0

3 years ago