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Free_Kalibri [48]
3 years ago
14

A pharmacist needs 20 liters of a 2% saline solution. She has a 1% solution and a 5% solution available. How many liters of the

1% solution and how many liters of the 5% solution should she mix to make the 2% solution?
Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

15 liters of 1% solution and 5 liters of 5% solution

Step-by-step explanation:

Let x liters of 1% solution needed and y liters of 5% solution needed to make this mixture.

We can say:

20(0.02) = x(0.01) + y(0.05)

0.4 = 0.01x + 0.05y

Also, we can write:

x + y = 20

x = 20 - y

We can put this into equation 1:

0.4 = 0.01x + 0.05y

0.4 = 0.01(20 - y) + 0.05y

0.4 = 0.2 - 0.01y + 0.05y

0.2 = 0.04y

y = 5 liters

Hence, x = 20 - 5 = 15 liters

We need,

15 liters of 1% solution and 5 liters of 5% solution

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Aloiza [94]

Distributive property

-8*4=-32          -8*9x=-72x

-32-72x=7(-2-11x)

7(-2)=-14      7(-11x)=-77x

-32-72x=-14-77x

Combine Like Terms

-32+14=-18       -77x+72x=-5x

-18=-5x

Divide both sides by -5 and theres your answer

6 0
3 years ago
Solve y=3x-7 and 4x+3y=18 by substitution
Schach [20]

Answer:

x = 3

y = 2

Step-by-step explanation:

4x + 3(3x - 7) = 18 <em>Substitute</em><em> </em><em>y</em>

4x + 9x - 21 = 18 <em>Simply</em>

13x - 21 = 18 <em>Add</em><em> </em><em>like</em><em> </em><em>terms</em>

13x = 39 <em>Add</em><em> </em><em>2</em><em>1</em>

x = 3 <em>Divide</em><em> </em><em>by</em><em> </em><em>1</em><em>3</em>

y = 3(3) - 7 <em>Substitute</em><em> </em><em>x</em>

y = 9 - 7 <em>Simply</em>

y = 2 <em>Subtract</em>

Let's check:

4(3) + 3(2) = 18

12 + 6 = 18

18 = 18

It works!

5 0
3 years ago
Read 2 more answers
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 46 o
meriva

Answer:

(a) 68% of the widget weights lie between <u>43 ounces</u> and <u>49 ounces</u>.

(b) The percentage of the widget weights lie between 43 and 87 ounces is 15.87%.

(c) The percentage of the widget weights lie below 76 is 100%.

Step-by-step explanation:

Let <em>X</em> = weight of widgets manufactured by Acme Company.

The distribution of the random variable <em>X</em> is, N (<em>μ </em>= 46, <em>σ</em>²<em> </em>=<em> </em>3²).

According to the Empirical Rule in a normal distribution with mean <em>µ</em> and standard deviation <em>σ</em>, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be broken into three parts:

  • 68% data falls within 1 standard deviation of the mean.                       That is P (µ - σ ≤ X ≤ µ + σ) = 0.68.
  • 95% data falls within 2 standard deviations of the mean.                   That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95.
  • 99.7% data falls within 3 standard deviations of the mean.                   That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.

(a)

According to the Empirical rule, 68% data falls within 1 standard deviation of the mean.

P (µ - σ ≤ X ≤ µ + σ) = 0.68.

Compute the upper and lower values as follows:

<em>µ</em> - <em>σ</em> = 46 - 3 = 43 ounces

<em>µ</em> + <em>σ</em> = 46 + 3 = 49 ounces

Thus, 68% of the widget weights lie between <u>43 ounces</u> and <u>49 ounces</u>.

(b)

Compute the probability of the widget weights lie between 43 and 87 ounces as follows:

P(43

                          =P(-1

*Use a <em>z</em>-table.

The percentage is, 0.1587 × 100 = 15.87%.

Thus, the percentage of the widget weights lie between 43 and 87 ounces is 15.87%.

(c)

Compute the probability of the widget weights lie below 76 as follows:

P(X

                  =P(Z

*Use a <em>z</em>-table.

The percentage is, 1 × 100 = 100%.

Thus, the percentage of the widget weights lie below 76 is 100%.

8 0
3 years ago
What is the gcf of 2,4a
-BARSIC- [3]
4.

2,4

4

Hope this helps!
3 0
3 years ago
7.3×9.6 show your work
Alex_Xolod [135]
            1
            7.3
         x 9.6 
          -------  
           438
      + 647 0
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6 0
3 years ago
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