I wrote the domain and range in interval notation, not sure if that’s how you’re asked to do it. This is how I was taught to state the domain/range of a graph.
Well, remember we can't take the square root of a negative
so we see that we have

so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input

for y1
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7
Answer:
8x^2+19x
Step-by-step explanation:
Simplify the expression by combining like terms. Terms which look a like and sound a like should be added together.
3x^2+7x+3+5x^2+12x
x^2 terms: 3x^2+5x^2=8x^2
x terms: 7x+12x=19x
constants: 3
Together is is 8x^2+19x+3.
1. x+½
2. 82-x
3. 4(x+3/10)
4. 2x-21
5.2x²
6. ⅓(x+53)
Answer: The answer for x is 6.75. The answer for y 6.75.
Step-by-step explanation:
You are going to mutiple 0.75 x 9 = 6.75. Then, mutiple 0.50 x 9= 4.5. Hope this works.