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blsea [12.9K]
3 years ago
15

-8(4+9x)=7(-2-11x) please help me solve this i have no clue and this is my math homework

Mathematics
1 answer:
Aloiza [94]3 years ago
6 0

Distributive property

-8*4=-32          -8*9x=-72x

-32-72x=7(-2-11x)

7(-2)=-14      7(-11x)=-77x

-32-72x=-14-77x

Combine Like Terms

-32+14=-18       -77x+72x=-5x

-18=-5x

Divide both sides by -5 and theres your answer

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Kelli has a family photograph with a width of 6 in and a height of 8 in. She wants to enlarge the photograph so that it’s width
Gelneren [198K]

Answer:20 Inches

Step-by-step explanation:

it is enlarged by 2.5 so you multiple the height (8) by 2.5 as well

6 0
3 years ago
Simplify 4 to the 11th power over 4 to the -8th power
madam [21]

Answer:

274878070200

Step-by-step explanation:

4 to the power 11 = 4194304

4 to the power -8 = 0.00001525878

4194304/0.00001525878 = 274878070200

3 0
3 years ago
Si f(x) es igual a raiz de x al cuadrado menos 16 determinar f(5),f(4),f(6),f(3)
Nadusha1986 [10]

Aplicando la función, los valores numéricos son :

f(5) = -11

f(4) = -12

f(6) = -10

f(3) = -13

La función es dada por:

f(x) = (\sqrt{x})^2 - 16  = x - 16

Para los valores numéricos, reemplazamos x, luego:

f(5) = 5 - 16 = -11

f(4) = 4 - 16 = -12

f(6) = 6 - 16 = -10

f(3) = 3 - 16 = -13

Un problema similar es dado en brainly.com/question/7037337

4 0
3 years ago
What set of reflections would carry rectangle ABCD onto itself?
Dvinal [7]

Answer:

  y=x, x-axis, y=x, y-axis

Explanation:

Reflecting the figure across three axes just moves it from one quadrant to another. It does not map the figure to itself.

Reflecting across the line y=x moves it from quadrant II to IV or vice-versa. If it is in quadrant I or III, it stays there. So the sequence of reflections x-axis (moves from I to IV), y=x (moves from IV to II), x-axis (moves from II to III), y=x (stays in III) will not map the figure to itself.

However, the last selection will map the figure to itself. The initial (and final) figure location, and the intermediate reflections are shown in the attached. The figure starts and ends as blue, is reflected across y=x to green, across x-axis to orange, across y=x to red, and finally across y-axis to blue again.

7 0
3 years ago
If r || s and M&lt;5 = 128, what’s is M&lt;1??<br><br> A. 128<br> B. 59<br> C. 62<br> D. 64
Fudgin [204]
We have been given that r is parallel to s. Now, if we look at angle 5 and angle 1, we can see that they are corresponding angles on parallel lines. Corresponding angles are ALWAYS equal, so therefore, your answer is 128 degrees; option A! :)

Hope this helped!
7 0
3 years ago
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