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oksano4ka [1.4K]

2 years ago

7

What is the gcf of 2,4a

1 answer:

-BARSIC- [3]2 years ago

3 0

4.

2,4

4

Hope this helps!

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Hi. I need help with these questions (see image)<br>Please show workings.<br>

pantera1 [17]

Answer:

see explanation

Step-by-step explanation:

Using the chain rule

Given

y = f(g(x)), then

$\frac{dy}{dx}$ = f'(g(x)) × g'(x) ← chain rule

and the standard derivatives

$\frac{d}{dx}$ ( $log_{a}$ x ) = $\frac{1}{xlna}$ , $\frac{d}{dx}$ (lnx) = $\frac{1}{x}$

(a)

Given

y = $log_{a}$ $\sqrt{(1+x)}$

$\frac{dy}{dx}$ = $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{d}{dx}$ ( $(1+x)^{\frac{1}{2} }$

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2}$ $(1+x)^{-\frac{1}{2} }$ × $\frac{d}{dx}$ (1 + x)

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2\sqrt{(1+x)} }$ × 1

= $\frac{1}{2lna(1+x)}$

= $\frac{1}{(1+x)lna^2}$

(b)

Given

y = ln sinx

$\frac{dy}{dx}$ = $\frac{1}{sinx}$ × $\frac{d}{dx}$ (sinx)

= $\frac{1}{sinx}$ × cosx

= $\frac{cosx}{sinx}$

= cotx

5 0

2 years ago

Complete the following sentences.Mark is rolling a number cube with sides labeled 1 through 6 and is looking for the probability

max2010maxim [7]

Total number of outcomes = 6
Number of ways the event occurs = 5
Probability = 5/6

6 0

2 years ago

A penny and a nickel are tossed. Describe the sample space of the experiment.

Irina-Kira [14]

Sample space would be:

(H,H), (H,T), (T,T), (T,H)

Here I have used H for heads and T for Tails... first coin for penny second for nickel...ok

Did you understand???

5 0

2 years ago

Can someone help me with these to please I’m kinda stuck on them lol

White raven [17]

Step-by-step explanation:

m+3=9

m=9-3=6

The second question I guess that it is solved like

2x+5=11

2x=11-5

2x=6

X=3

Or the other qusetion 5x-8=27

5x=19

X=19/5

I don't know the machine so sorry

7 0

2 years ago

Consider a normal distribution curve where the middle 85 % of the area under the curve lies above the interval ( 8 , 14 ). Use t

NeTakaya

Answer:

$\mu = 11$

$\sigma = 2.08$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Middle 85%.

Values of X when Z has a pvalue of 0.5 - 0.85/2 = 0.075 to 0.5 + 0.85/2 = 0.925

Above the interval (8,14)

This means that when Z has a pvalue of 0.075, X = 8. So when $Z = -1.44, X = 8$ . So

$Z = \frac{X - \mu}{\sigma}$

$-1.44 = \frac{8 - \mu}{\sigma}$

$8 - \mu = -1.44\sigma$

$\mu = 8 + 1.44\sigma$

Also, when X = 14, Z has a pvalue of 0.925, so when $X = 8, Z = 1.44$

$Z = \frac{X - \mu}{\sigma}$

$1.44 = \frac{14 - \mu}{\sigma}$

$14 - \mu = 1.44\sigma$

$1.44\sigma = 14 - \mu$

Replacing in the first equation

$\mu = 8 + 1.44\sigma$

$\mu = 8 + 14 - \mu$

$2\mu = 22$

$\mu = \frac{22}{2}$

$\mu = 11$

Standard deviation:

$1.44\sigma = 14 - \mu$

$1.44\sigma = 14 - 11$

$\sigma = \frac{3}{1.44}$

$\sigma = 2.08$

7 0

2 years ago