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erica [24]
3 years ago
8

Explain how you would graph the line containing a slope of-1/5 that goes through the point (1,-4)​

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

y= -1/5x + 1/5

Step-by-step explanation:

y- y1 = m(x - x1)

Slope m=-1/5

(1, -4)

1 = y1

-4 = x1

y- 1 = -1/5(x-(-4))

y-1 = -1/5(x+4)

y-1= -1/5(x)+ -1/5(4)

y-1 = -1/5x + -4/5

add one to both sides

y= -1/5x + -4/5 + 1

y = -1/5x + 1/5

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Answer:

Only option D is one of the transformations needed.

Step-by-step explanation:

The graph of f(x)=x^2 is a positive parabola with x=0 as the zero in ordinates and also 0 as a zero x. This is, the graph passes in (0,0) and this is the only point it crosses both axis, then for every x value we will gave a positive f(x).

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So, the three transformations needed are:

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Sorry for the mistake!

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k = -9/3 
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3 years ago
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