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Ilia_Sergeevich [38]
3 years ago
11

Can someone do #1 and #2 I don't really get the answer. My teacher hasn't explain anything. He just gave us the paper and we got

ta do it and they're in the test this Friday. Please help?

Mathematics
1 answer:
Elenna [48]3 years ago
5 0
1) f(x) + g(x)

= 7√x + 4 + 2√x - 2

= √x(7 + 2) + 2

= 9√x + 2  [ Final Answer ]

2) f(x) - g(x)

= 7√x + 4 - (2√x - 2)

= 7√x + 4 - 2√x + 2

= √x(7 - 2) + 6

= 5√x + 6   [ Final Answer ]

Hope this helps!
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A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round
Neko [114]

Answer:

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 137, \sigma = 7

Find the z-score for a data value of 121.

This is Z when X = 121. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{121 - 137}{7}

Z = -2.29

The z-score for a data value of 121 is -2.29.

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Step-by-step explanation:

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Do you still need help with this question?
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Len's recipe for blueberry muffins calls for 110.25 g of brown sugar for the muffin batter and an additional 55.45 g of brown su
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