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3 years ago

Find the value of (256)-3/4help with steps pls

Mathematics

1 answer:

victus00 [196]3 years ago

4 0

Answer:

Step-by-step explanation:

(256)-3/4

=256*-3/4

=-768/4

=-192

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What does X equal? geometry

Otrada [13]

Answer:

x= 77

Step-by-step explanation:

The angle at 122 degrees is a linear pair with the isosceles triangle, meaning it makes 180 degrees.

180-122= 58 degrees

Since it is an isosceles triangle, the two angles at the bottom are both 58 degrees.

Let's use this info to find the degree at the top.

58+58= 116

There are 180 degrees in a triangle, so subtract 116 degrees we have so far to find the last angle.

180-116= 64 degrees

And since the angle at the top makes 90 degrees, we can subtract 64 degrees to find the smaller angle to the right of the 64 degree angle.

90-64= 26 degrees

And since a triangle has a total of 180 degrees, subtract the 26 degrees from 180.

180-26= 154 degrees.

And since it is an isosceles triangle, divide the remaining 154 degrees by 2 because they are both equal.

154/2= 77 degrees.

Your answer is 77 degrees.

3 0

2 years ago

5.1436 rounded to the nearest hundredth

tatiyna

Answer:

5.14

Step-by-step explanation:

ones.tenths hundredths

8 0

3 years ago

Read 2 more answers

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$