Please help with these 4 problems. See attachment

You can buy 3 apples at the Quick Market for $1.11. You can buy 5 of the

Cloud [144]

Stop and save because you save your money and get more apples

7 0

3 years ago

Multiple and convert to simplest form

Lady bird [3.3K]

Answer:

1)4

2)28

3)18.3

4)38.5

5)22.5

6)19.25

7)25.5

8)69.666

9)6.5

10)22.666

Step-by-step explanation:

To do this first you should convert the mix numbers into inproper fractions and then solve.

1)8/5*5/2=4

2)21/5*20/3=7*4

=28

3)33/4*20/9=11*5/3

=55/3

=18.33...

=18.3

4)35/6*33/5=7*11/2

=77/2

=38.5

5)22/8*90/11=45/2

=22.5

6)11/3*21/4=11*7/4

=77/4

=19.25

7)34/5*15/4=34*3/4

=25.5

8)22/3*57/6=11*19/3

=209/3

=69.666

9)39/8*4/3=13/2

=6.5

10)17/2*8/3=17*4/3

=68/3

=22.666

Hope you got this

If you have any doubt please ask me

If you need this in fraction form just check the attachment

5 0

3 years ago

What is the roots of the quadratic equation? 6x^2+5x-4=0

Rama09 [41]

x = $\frac{1}{2}$ or x = - $\frac{4}{3}$

consider the factors of the product 6 × - 4 = - 24 which sum to the coefficient of the x- term ( + 5)

the factors are + 8 and - 3 ( split the middle term using these factors

6x² - 3x + 8x - 4 = 0 ( factor by grouping )

3x(2x - 1) + 4(2x - 1 ) ( take out common factor of (2x - 1) )

= (2x - 1)(3x + 4) = 0

equate each factor to zero and solve for x

2x - 1 = 0 ⇒ x = $\frac{1}{2}$

3x + 4 = 0 ⇒ x = - $\frac{4}{3}$

4 0

4 years ago

Read 2 more answers

A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye

Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we select appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{x}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{x}=\sqrt{n}\sigma$

The information provided is:

μ = $970

σ = $129

n = 102

Since the sample size is quite large, i.e. n = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

$\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)$