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CaHeK987 [17]
2 years ago
15

AD ??????? so confused what the

Mathematics
1 answer:
Andre45 [30]2 years ago
4 0

Answer:

3.6 cm

Step-by-step explanation:

<u>Triangle Proportionality Theorem</u>

BD : DE = BA : AC

⇒ 6 : 10 = BA : 16

⇒ \mathsf{\dfrac{6}{10} = \dfrac{BA}{16}}

⇒ \mathsf{BA=\dfrac{6}{10} \times16}

⇒ BA = 9.6

AD = BA - BD

⇒ AD = 9.6 - 6 = 3.6 cm

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PLS HELP ASAP PLSSS IT DETECTS IF ITS RIGHT OR WRONG HELPPP
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Answer:

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Step-by-step explanation:

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There are 8 swimmers in the swimming club. The club bought c swimming caps to split among its members. Write an expression that
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2 years ago
Read 2 more answers
1. Consider the following hypotheses:
Andrej [43]

Answer:

See deductions below

Step-by-step explanation:

1)

a) p(y)∧q(y) for some y (Existencial instantiation to H1)

b) q(y) for some y (Simplification of a))

c) q(y) → r(y) for all y (Universal instatiation to H2)

d) r(y) for some y (Modus Ponens using b and c)

e) p(y) for some y (Simplification of a)

f) p(y)∧r(y) for some y (Conjunction of d) and e))

g) ∃x (p(x) ∧ r(x)) (Existencial generalization of f)

2)

a) ¬C(x) → ¬A(x) for all x (Universal instatiation of H1)

b) A(x) for some x (Existencial instatiation of H3)

c) ¬(¬C(x)) for some x (Modus Tollens using a and b)

d) C(x) for some x (Double negation of c)

e) A(x) → ∀y B(y) for all x (Universal instantiation of H2)

f)  ∀y B(y) (Modus ponens using b and e)

g) B(y) for all y (Universal instantiation of f)

h) B(x)∧C(x) for some x (Conjunction of g and d, selecting y=x on g)

i) ∃x (B(x) ∧ C(x)) (Existencial generalization of h)

3) We will prove that this formula leads to a contradiction.

a) ∀y (P (x, y) ↔ ¬P (y, y)) for some x (Existencial instatiation of hypothesis)

b) P (x, y) ↔ ¬P (y, y) for some x, and for all y (Universal instantiation of a)

c) P (x, x) ↔ ¬P (x, x) (Take y=x in b)

But c) is a contradiction (for example, using truth tables). Hence the formula is not satisfiable.

7 0
3 years ago
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