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podryga [215]
3 years ago
12

g There are 3 signal transmitters T1,T2 and T3. Each one sends a signal to a receiver R and R sends three signals back to the th

ree transmitters in a random way, so that each transmitter sends a signal and also receive a signal. What is the probability that at least one transmitter receives the signal sent by itself? What if there are n transmitters?
Mathematics
1 answer:
ANEK [815]3 years ago
7 0

Answer:

Recall that probability is given as; the number of required outcome over the number of total possible outcome.

The probability that a transmitter receives the signal being sent by itself is given as \frac{1}{3}.

when there are n transmitters, the probability will be given as \frac{1}{n}

Step-by-step explanation:

Probability simply the likelihood of an event occurring or not occurring.

Probability therefore is given as; the number of required outcome over number of possible outcome.

In the case of the first part above we have the number of required outcome to be at least one divided by the number of possible outcome which is 3.

while in the second part we have the number o possible outcome to be n.

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We need to define our outcomes and events.

 

Finding the probability<span> of each event occurring separately, and then multiplying the probabilities is the step to <span>finding  the probability</span> of two independent events that occur in sequence.

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To solve this problem, we take note of this:</span>

 

The roll of the two dice are denoted by the pair

(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }

Each pair is an outcome. There are 36 pairs and each has probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the number of rolls N until we observe doubles is a geometric (p) random variable and has expected value E[N] = 1/p = 6.

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3 years ago
Ms. Chang has 16 students in her class. She wants to send 3 of her students to pick up books for the class. How many combination
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4 0
3 years ago
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Which statement is correct?
Arisa [49]

Answer:

2.06 \times 10^-^2 = 206

1.88 \times 10^-^1 = 18.8

206 \times 18.8 = 3,872.8

7.69 \times 10^-^2 = 769

2.3 \times 10^-^5  = 230,000

=\frac{769}{230000}

= 0.00334

therefore,

3,872.80 > 0.00334

Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-

2.3x10-5

7.69 x 10"

(2.06 x 10-2x1.88x10-)>

2.3x10-5

(2.06x 10-2X(1.88x 10-1)-7.69x104

2.3x10-5

Given that;

2.06 \times 10^-^2 = 206

1.88 \times 10^-^1 = 18.8

206 \times 18.8 = 3,872.8

7.69 \times 10^-^2 = 769

2.3 \times 10^-^5  = 230,000

=\frac{769}{230000}

= 0.00334

therefore,

3,872.80 > 0.00334

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