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podryga [215]
3 years ago
12

g There are 3 signal transmitters T1,T2 and T3. Each one sends a signal to a receiver R and R sends three signals back to the th

ree transmitters in a random way, so that each transmitter sends a signal and also receive a signal. What is the probability that at least one transmitter receives the signal sent by itself? What if there are n transmitters?
Mathematics
1 answer:
ANEK [815]3 years ago
7 0

Answer:

Recall that probability is given as; the number of required outcome over the number of total possible outcome.

The probability that a transmitter receives the signal being sent by itself is given as \frac{1}{3}.

when there are n transmitters, the probability will be given as \frac{1}{n}

Step-by-step explanation:

Probability simply the likelihood of an event occurring or not occurring.

Probability therefore is given as; the number of required outcome over number of possible outcome.

In the case of the first part above we have the number of required outcome to be at least one divided by the number of possible outcome which is 3.

while in the second part we have the number o possible outcome to be n.

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To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}

4 0
1 year ago
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Answer:

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Answer:

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Step-by-step explanation:

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