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vaieri [72.5K]
3 years ago
6

Factor p^4-81 completely showing all work.

Mathematics
1 answer:
3241004551 [841]3 years ago
8 0

Answer:

Step-by-step explanation:

p^4-81=(p^2)^2-9^2=(p^2+9)(p^2-9)=(p^2-9(-1))(p+3)(p-3)\\=(p^2-9i^2)(p+3)(p-3)\\=(p+3i)(p-3i)(p+3)(p-3)

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