Factor p^4-81 completely showing all work.

Mathematics

1 answer:

3241004551 [841]3 years ago

8 0

Answer:

Step-by-step explanation:

$p^4-81=(p^2)^2-9^2=(p^2+9)(p^2-9)=(p^2-9(-1))(p+3)(p-3)\\=(p^2-9i^2)(p+3)(p-3)\\=(p+3i)(p-3i)(p+3)(p-3)$

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Step-by-step explanation:

(a) Taking the natural log of both sides, we have ...

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