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ehidna [41]
3 years ago
13

The average age for a person getting married for the first time is 26 years (U.S. News and World Report, June 6, 1994). Assume t

he ages for first marriages have a normal distribution with a standard deviation of four years.90% of people getting married for the first time get married before what age?
Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer: 90% of people getting married for the first time get married before age of 31.13.

Step-by-step explanation:

Given : The average age (\mu) for a person getting married for the first time is 26 years (U.S. News and World Report, June 6, 1994).

We assume that  the ages for first marriages have a normal distribution with a standard deviation (\sigma) of 4 years.

Let x be the age before that 90% of people getting married for the first time get married.

From z-table , the value corresponds to p-value of 0.90 is 1.28155.

Formula : z=\dfrac{x-\mu}{\sigma}

1.28155=\dfrac{x-26}{4}\\\\ x-26=4\times1.28155\\\\ x-26=5.1262\\\\ x=5.1262+26=31.1262\approx31.13

Hence, 90% of people getting married for the first time get married before age of 31.13.

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The length of a rectangle is five times its width.
Vera_Pavlovna [14]

Answer:

72

Step-by-step explanation:

l = 5w

A = l*w

180 = 5w *w

180 = 5w^2

Divide each side by 5

180/5 = 5w^2 /5

36 = w^2

Taking the square root of each side

sqrt(36) = sqrt(w)^2

6 =w

l = 5w = 5*6 = 30

The perimeter is

P = 2(l+w)

P = 2(6+30) = 2(36) = 72

4 0
3 years ago
Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in
Luda [366]

ANSWER: 32 five-dollar bills

======

EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.

Divide both sides of equation (II) by 5 so our numbers become smaller

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.

Rearrange (I) to solve for y so that we can substitute into (II)

\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}

Substituting this into equation (II) for the y:

\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

y = 38 - 32 = 6

32 five-dollar bills and 6 ten-dollar bills

7 0
3 years ago
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denis-greek [22]
-6.4 – 4(-2.8)
-6.4 – - 11.2 = 4.8

Your answer is B: 4.8
7 0
3 years ago
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krok68 [10]

Answer:

4 + 0.32x  

Step-by-step explanation:

       0.32 = cost of one text message

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4 + 0.32x = monthly cost of x text messages

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Since we have a transverse line that cuts through the straight line parallel to the height, then we can see that the angles are divided into two sections.

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3 years ago
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