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3 years ago

Please help. Please explain. Please get it correct!

Mathematics

2 answers:

dangina [55]3 years ago

5 0

Answer:5/6

Step-by-step explanation:

Lyrx [107]3 years ago

4 0

Answer:

3965566

Step-by-step explanation:

because am smart

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Is the square root of 15 greater than, less then , or equal to 4?

Sever21 [200]

Answer:

less than 4

Step-by-step explanation:

the closest perfect square root to 15 is the square root of 16, which produces the number 4. since 16 is greater than 15, the value of the square root of 15 is less than 4.

hope this helps!

4 0

4 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

4 years ago

Find x if h(x)=-2<br> Please Helppp :) ill mark brainliest

Paladinen [302]

Answer:

x=4

Step-by-step explanation:

hope this helps:)

7 0

3 years ago

Read 2 more answers

Estimate the product 28 2/3 x 4/5

Leona [35]

Answer:

23.2, exact is 22.9333334

Step-by-step explanation:

28 2/3 is around 28.5 ,4/5 is .75

28.5 * .75 = 21.375

8 0

3 years ago

9 pencils cost $7.74.<br> Which equation would help determine the cost of 6<br> pencils?

eduard

The answer is A. If 9 pencils cost $7.74, we have to divide the total cost ($7.74) by the number of pencils (9) to obtain the price of 1 pencil. Now that we have the price of 1 pencil, to obtain the cost of 6 of them we simply multiply the result by six.

6 0

3 years ago