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3 years ago

If f(x) = –x3, g(x) = 3x2 – 1, and h(x) = 2x + 5, what is the degree of [f o g o h](x)?

Mathematics

2 answers:

Alenkinab [10]3 years ago

5 0

Answer:

The degree of [f o g o h](x) is 6.

Step-by-step explanation:

We are given the following information:

$f(x) = -x^3\\g(x) = 3x^2 - 1\\ h(x) = 2x + 5$

we have to find degree of [f o g o h](x)

[f o g o h](x) =

$f \circ g \circ h = f(g(h(x)))$

Putting the values,

$f(g(h(x)))\\\\=f(g(2x + 5)\\\\= f(3(2x+5)^2-1)\\\\= -(3(2x+5)^2-1)^3\\\\= -(3(4x^2+25+20x)-1)^3\\\\=-(12x^2+60x+74)^3\\\\= -1728x^6-25920x^5-161568x^4-535680x^3-996336x^2-985680x-405224$

The degree of above expression is 6.

Thus, the degree of [f o g o h](x) is 6.

yan [13]3 years ago

4 0

I reckon the degree will be 6

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<h3>Equation of an ellipse</h3>

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Learn more about ellipse here:

brainly.com/question/26679189

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