Answer:
ASA
Step-by-step explanation:
∠BAC ≈ ∠CAD
AC = AC
∠BCA ≈ ∠ACD
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
We are tasked to determine the natural logarithm when x = 0.6.
x = 0.6, applying natural logarithm on both sides, we have it:
ln x = ln 0.6 using a scientific calculator, enter ln 0.6 and then this would give an answer of -0.5108256238
As per instruction, we are required to round the answer to the nearest hundredth such as the final answer is -0.51.
The answer is the letter "B".
The points are; (7/2, -1/2).
<h3>What is the given point?</h3>
Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.
Then to obtain the slope of the curve we have; y = 19 - 2x
dy/dx = 2
Using the relation;
m1m2 = -1
m2 = -1/2
Hence;
y = 1/4 - 5(-1/2)
y = 1/4 + 5/2
y = 7/2
Thus the points are; (7/2, -1/2)
Learn more about normal curve:brainly.com/question/10664419
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