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viva [34]
3 years ago
6

Compute the value of the discriminant and give the number of real solutions of the quadratic equation.

Mathematics
1 answer:
Sergio039 [100]3 years ago
4 0
-2x^2+6x-3=0 \\ \\
a=-2 \\ b=6 \\ c=-3 \\ \Delta=b^2-4ac=6^2-4 \times (-2) \times (-3)=36-24=12

The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.
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