3 years ago

Compute the value of the discriminant and give the number of real solutions of the quadratic equation.

1 answer:

4 0

$-2x^2+6x-3=0 \\ \\
a=-2 \\ b=6 \\ c=-3 \\ \Delta=b^2-4ac=6^2-4 \times (-2) \times (-3)=36-24=12$

The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.

You might be interested in

A square has an area of 16 square millimeters. What is the length of each side of the square? 2 mm 8 mm 12 mm 4 mm

USPshnik [31]

Answer:

4 mm

Step-by-step explanation:

$\sqrt{16}$ = 4

So, the answer is 4 mm.

<h2><u><em>Please mark as Brainliest!!!</em></u></h2>

6 0

3 years ago

Read 2 more answers

The diagonals of a quadrilateral bisect at right angles. What type of quadrilateral is this?

arsen [322]

square

Step-by-step explanation:

8 0

3 years ago

Which should be the first step in solving the equation 1.2w-3.8=12.4

zaharov [31]

Answer:

+3.8 to each side

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find an equation for the nth term of the arithmetic sequence. -15, -6, 3, 12, ...

Mariulka [41]

Answer: $t_{n}=-15+9(n-1)$

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is given as:

$t_{n}=a+(n-1)d$

$a =$ first term = -15

$d =$ common difference = -6 - (-15) = 9

$n =$ number of terms

substituting into the formula , we have :

$t_{n} = -15+(n-1)9$

$t_{n}=-15+9(n-1)$

5 0

3 years ago

11.REINFORCE The lengths of three sides of a triangle are 2x, 3x - 4, and x+4. Find a value of x that makes the triangle equilat

mash [69]

Answer:

x=4

Step-by-step explanation:

It suffices to equate any two sides and then check whether the solution is valid for the third side.

Taking 2x and 3x-4 and equating:

2x = 3x-4

x = 4

This means the sides are both of length 8. Now check whether for x=4 the third side is also of length 8:

x+4=4+4=8

which indeed works out confirming x=4 being a valid solution

5 0

3 years ago