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2 years ago

Compute the value of the discriminant and give the number of real solutions of the quadratic equation.

1 answer:

4 0

$-2x^2+6x-3=0 \\ \\
a=-2 \\ b=6 \\ c=-3 \\ \Delta=b^2-4ac=6^2-4 \times (-2) \times (-3)=36-24=12$

The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.

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For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

What is the volume of this triangular pyramid?

valentina_108 [34]

Answer:

37.5 or 37 1/2

Step-by-step explanation:

You need to multiply length times width times height and then divide it by two.

5 0

2 years ago

Read 2 more answers

Esmerelda flips a coin and draws a card. What is the possibility that she gets “heads” and a black card?

elena55 [62]

The possibility of flipping heads is 1 in 2 (1/2)
the possibility of pulling a black card is 26 in 52 (26/52) which equals 1 in 2 (1/2)
multiply those together and you get 1 in 4, 1/4, or a 25%

7 0

2 years ago

Read 2 more answers

Ok is it 15/28 or 75/135 thatx is evuviulent to 25/45

Aleonysh [2.5K]

You also need to brake down this answer farther.

4 0

2 years ago

(Score for Question 2: ___ of 5 points)

GuDViN [60]

Answer:

Since you don't show your triangles, I'm guessing it is this one...?

△DWP D = (-2, 4), W = (-1, 2), P = (3, 3)

△MJS M = (-4, -4), J = (-2, -3), S = (-3, 1)

There are 2 steps:

1. 90° counterclockwise rotation about the origin

2. Translation downward 2 units

Step-by-step explanation:

1. 90° counterclockwise rotation about the origin = (x, y) to (-y, x),

D moves from (-2, 4) to (-4, -2)

W moves from (-1, 2) to (-2, -1)

P moves from (3, 3) to (-3, 3)

2. Translation downward 2 units = (x, y) to (x, y-2),

D moves from (-4, -2) to (-4, -4) = M

W moves from (-2, -1) to (-2, -3) = J

P moves from (-3, 3) to (-3, 1) = S

Therefore △DWP IS congruent to △MJS.

4 0

2 years ago