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3 years ago

What is the opposite of -4

Mathematics

2 answers:

Marina86 [1]3 years ago

5 0

The answer is 4!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Katen [24]3 years ago

3 0

4 is the opposite of -4.

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What is the perpendicular slope intercept form?

In-s [12.5K]

Answer:

y = -1/2x + 2.5

Step-by-step explanation:

- slope of a perpendicular line is the negative reciprocal of the original slope (2 in this case) so y = -1/2 x + c

- to find c we substitute the values from the given point into the equation

(0) = -1/2*(5) + c

- rearrange and calculate and you'll get c = 5/2 or 2.5

- replace the value of c and now you've got y = -1/2x + 2.5

6 0

2 years ago

A ________ is a number that compares part of an object or a set with the whole object or set. What is the blank?

katovenus [111]

Answer:

Fraction

Step-by-step explanation:

6 0

2 years ago

Identify the volume of a cone with base area 64π m2 and a height 4 m less than 3 times the radius, rounded to the nearest tenth.

melomori [17]

V=basearea times 1/3 times height
basearea=64π m2
hmm, they try to make it difficult

basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9

h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20

v=1/3*64pi*20=1280pi/3 m^3=1350.4

C

4 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

Please help ill give brainiest

vaieri [72.5K]

Answer:

give it

Step-by-step explanation:

the answer is m=1/4

8 0

2 years ago

Read 2 more answers