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Maru [420]
3 years ago
14

20%29%29%20%2B%20%20%7B2%7D%5E%7B2%7D%20%20%3D%200" id="TexFormula1" title=" {2}^{x} - 3( {2}(^{x} + \frac{1}{2} )) + {2}^{2} = 0" alt=" {2}^{x} - 3( {2}(^{x} + \frac{1}{2} )) + {2}^{2} = 0" align="absmiddle" class="latex-formula">
Can someone solve this equation?​
Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0

Answer:   \huge\boxed{x=log_2\frac{12\sqrt{2}+4}{17}}

Step-by-step explanation:                                                                       \displaystyle\ \bigg{2^x-3(2^{x+\frac{1}{2} }})+2^2=0 \qquad  ; \ \ \boxed{t=2^x} \\\\t-3t\sqrt{2} +4=0  \\\\ t(1-3\sqrt{2} )=-4 \\\\ t=\frac{4}{3\sqrt{2} -1} \cdot \frac{3\sqrt{2}+1 }{3\sqrt{2}+1 } =\frac{12\sqrt{2}+4}{17}  \\\\\\2^x=\frac{12\sqrt{2}+4}{17} \\\\x=log_2 \ \ \frac{12\sqrt{2}+4}{17}

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