3 years ago

HELPPPPPPPP MEEEEEEE PLZZZZZZZZ

Mathematics

1 answer:

olga55 [171]3 years ago

5 0

I think it’s the 3rd one

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Solve the equation on the<br> interval [0, 2π).<br> √2 cos x - 1 = 0

jek_recluse [69]

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Step-by-step explanation:

$\sqrt{2} cos x-1=0\\cos x=\frac{1}{\sqrt{2} } =cos (\frac{\pi }{4} ),cos (2\pi -\frac{\pi }{4} )\\cos x=cos(2n\pi +\frac{\pi }{4} ),cos(2n\pi +\frac{7\pi }{4} )\\x=2n\pi +\frac{\pi }{4} ,2n\pi +\frac{7\pi }{4} \\n=0\\x=\frac{\pi }{4} ,\frac{7\pi }{4}$