Use front-end estimation to add 495 + 650 + 875. Indicate the three digits that you will add first?

FOR 12 POINTS I NEED HELP ASAP! Consider the system of linear equations. 5 x + 10 y = 15. 10 x + 3 y = 13 To use the linear comb

Romashka [77]

Answer:

Do you mean which equation should the 5x+10=15 be multiplied to?

it would be -2

Step-by-step explanation:

This is because 5 times -2 is -10

and so when you add the (now) x value of the first equation to the x value of the second equation, it gets 0

which makes it eliminated!

-10x+10x=0

8 0

4 years ago

If angle 1 is 110°, what would the other angle measures

Iteru [2.4K]

Answer:

If Angle 1 is 110,

then the second angle to complete the straight angle (180 degrees) is...

180 - 110 = 70

Angle 2 = 110 (same as Angle 1, plus it's obtuse)

Angle 3 = 70 (it's acute)

Angle 4 = 70 (same as Angle3, plus it's acute)

3 0

3 years ago

Read 2 more answers

Experience raising New Jersey Red chickens revealed the mean weight of the chickens at

Nikolay [14]

Answer:

p-value = 0.1277

Step-by-step explanation:

p-value is the probability value tell us how likely it is to get a result like this if the Null Hypothesis is true.

Firstly we find the mean and standard deviation of the given data set.

⇒ Mean = $\frac{4.41 +4.37+ 4.33+ 4.35 +4.30 +4.39 +4.36+ 4.38+ 4.40+ 4.39}{10}$

⇒ Mean = 4.368

$Standard deviation(\sigma) = \sqrt{\frac{1}{n}\sum_{i=1}^{n}{(x_{i}-\bar{x})^{2}} }$

where, $\bar{x}$ is mean of the distribution.

⇒ Standard Deviation = 0.034

Applying t- test:

Let out hypothesis is:

H₀: μ = 4.35

H₁: μ ≠ 4.35

Now,

Here, μ = Population Mean = 4.35

$\bar{x}$ = Sample Mean = 4.368

σ = Standard Deviation = 0.034

n = 10

$t=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all values we get, t = 1.6777 with (10 -1) = 9 degree of freedom.

Then the p-value at 99% level of significance.

⇒ p-value = 0.1277

6 0

4 years ago

What is the range in interval notation of the function graphed below?

attashe74 [19]

Answer:

Range tells you how high and low the graph of this parabola goes in the “y” (vertical) directions.

1. We can see that the parabola peaks on the y-axis at y = 4. That’s as HIGH as it goes.

2. We also see that both sides of the parabola descend to the level of y = -7. That’s as LOW as it is shown to go.

So putting these together, we say the Range is given by:

-7 <= y <= 3

AMBIGUITY WARNING:

Because the two branches of the parabola go fall right down to the edge of the picture boundary, it’s UNCLEAR whether the parabola truly stops at y = -7 or CONTINUES on (to negative infinity).

In THAT case, the RANGE simplifies to:

Y <= 4

Done.

Step-by-step explanation:

5 0

2 years ago

FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli

____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0

1 year ago