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Otrada [13]
3 years ago
9

I really need help with #2

Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Answer:

do u still need help. I can help

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Im getting my grade up soo help
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Where is pic…………………,,,,,
4 0
2 years ago
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Find the magnitude and direction (in degrees) of the vector. (Assume 0° ≤ θ < 360°. Round the direction to two decimal places
podryga [215]
V=<12,5>
Magnitude
|v| = sqrt(12^2+5^2) = 13

Direction
theta
= atan2(5,12)
= atan(5/12)
= 22.62 degrees

5 0
4 years ago
A scale drawing of a patio is shown here. The scale is 4 inches : 6.8 feet. What is are length and width of the patio? Find the
mars1129 [50]

Answer:

A

Step-by-step explanation:

Divide 6.8ft by 4in then you get 1.7 and the multiply 15 an 14 by 1.7 then you get 25.5 and 23.8 then multiply 25.5 with 23.8 and get 606.9

4 0
3 years ago
Read 2 more answers
Jayden has been reading a 275275275-page book for english class. on average, he has read about 101010 pages in 151515 minutes (\
Vitek1552 [10]
<span>75 pages.
   OK. Lots of copying errors here. I'll be using 275 page book, reading 10 pages per 15 minutes, skimming 15 pages per 10 minutes, 5 hours and 50 minutes to complete the book.
   To make things easier, first convert the time to just minutes. So 5 * 60 + 50 = 300 + 50 = 350 minutes.

   Now let's use the variable X for the number of minutes spent skimming and (350-X) for the number of minutes spent reading.
 X * 15/10 + (350 - X)*10/15 = 275

   Solve for X.
 X * 15/10 + (350 - X)*10/15 = 275
 X * 15/10 + 350*10/15 - X*10/15 = 275
 X * 15/10 - X*10/15 = 275 - 350*10/15
X(15/10 - 10/15) = 275 - 3500/15
 X(45/30 - 20/30) = 825/3 - 700/3
 X(25/30) = 125/3
 X = 125/3 * 30/25 = 125/1 * 10/25 = 5/1 * 10/1 = 50/1 = 50
   So Jayden spent 50 minutes skimming. And at the rate of 15 pages every 10 minutes, he skimmed 50*15/10 = 750/10 = 75 pages.</span>
7 0
3 years ago
Write an equation in point slope form for the line that passes through (-5,6) and (-3,-9).
Finger [1]

\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\qquad&#10;(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-9})&#10;\\\\\\&#10;slope = m\implies&#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-9-6}{-3-(-5)}\implies \cfrac{-9-6}{-3+5}\implies -\cfrac{15}{2}


\bf \begin{array}{|c|ll}&#10;\cline{1-1}&#10;\textit{point-slope form}\\&#10;\cline{1-1}&#10;\\&#10;y-y_1=m(x-x_1)&#10;\\\\&#10;\cline{1-1}&#10;\end{array}\implies y-6=-\cfrac{15}{2}[x-(-5)]\implies y-6=-\cfrac{15}{2}(x+5)&#10;\\\\\\&#10;y-6=-\cfrac{15}{2}x-\cfrac{75}{2}\implies y=-\cfrac{15}{2}x-\cfrac{75}{2}-6\implies y=-\cfrac{15}{2}x-\cfrac{87}{2}

8 0
3 years ago
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