I really need help with #2

zmey [24]

2/5 van not be simiplified because 2 and 5 dont have a common factor lower than them

4 0

3 years ago

There was a triangle ABC with sides 15, 20, and 10. One of the sides of a triangle, which is similiar to ABC is 60. What are the

wlad13 [49]

Answer:

The possible pairs of sides are 90 and 120, 30 and 45, and 80 and 40.

Step-by-step explanation:

We know that 60 is a multiple of 15, 20, and 30, so we multiply by each factor to find all possible pairs: 10x6=60, 20x6=120, and 15x6=90, that gives your first pair, 90 and 120.

We have now multiplied our first factor, 6. Now we need to multiply our second factor, 3: 20x3=60, 15x3=45, and 10x3=30. That gives your second pair, 30 and 45.

Finally, we need to multiply by our 3rd factor, 4: 15x4=60, 20x4=80, and 10x4=40. That gives you your final possible pair, 80 and 40.

I hope this helps :-)

3 0

3 years ago

A parabola intersects the x-axis at x=3 and x=9 what is the x-coordinate of the parabola's vertex?

KiRa [710]

Here we are given the x intercepts at x=3 and x=9

So let us try to make quadratic equation for this using given information.

We have factors in the form (x-a)(x-b)

where a and b are x intercepts given to us.

So rewriting in factored form:

$y=(x-3)(x-9)$

Now let us simplify it:

$y=x^{2}-12x+27$

Let us find the vertex now,

For a quadratic equation of the form:

$y=ax^{2}+bx+c$

For x coordinate , we have the formula,

$x=\frac{-b}{2a}$

So using this formula for our equation,

$x=\frac{-(-12)}{2(1)}$

So x = 6

Answer: The x-coordinate of the parabola's vertex is 6.

7 0

3 years ago

Read 2 more answers

Guys, I’m giving you at least 100 points for you to answer to my angles, triangles, and quadrilaterals word problem homework pac

frez [133]

Step-by-step explanation:

For question 22: Notice the congruent symbol on sides AB and CB; this shows that the triangle is isosceles, and in an isosceles triangle, the angles opposite congruent sides are congruent. Thus, angle A actually equals angle C.

In other the find B, it is know that all of the interior angles of a triangle must add to 180; thus, this can be written as: angle A + angle B + angle C = 180.

Since you already know angles A and C, subtract angle A and angle C from 180 to get angle B.

For question 23:

Notice that triangle DBC is an isosceles triangle, and that angle D and angle C are opposite of congruent sides, indicating that they are equal. Since the interior angles of a triangle must add up to 180, and you know that angle D equals angle C, you can find angle DBC by doing 180 - (2 * angle D).

Now that you have angle DBC, you can find angle CBA; since these two angles form a straight line, you know they must add to 180 degrees. Thus, 180 - angle DBC equals angle CBA.

Now, notice that triangle CBA is also isosceles, and that angles CBA and angle A are opposite congruent sides, indicating that they are also congruent. Thus, angle A equals angle CBA.

Hope this helps :)

4 0

2 years ago

Oblicz.Pamiętaj o kolejności wykonywania działań

SashulF [63]

Answer:

33.275

Step-by-step explanation:

1 step: Difference in brackets

$3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}$

2 step: $0.75\div\dfrac{1}{3}$

$0.75\div\dfrac{1}{3}=\dfrac{75}{100}\div \dfrac{1}{3}=\dfrac{3}{4}\times \dfrac{3}{1}=\dfrac{9}{4}$

3 step: $1.28\div 0.04$

$1.28\div 0.04=128\div 4=32 \ \text{Move point two decimal places}$

4 step:

$2\dfrac{1}{4}\times 1\dfrac{1}{6}=\dfrac{2\cdot 4+1}{4}\times \dfrac{1\cdot 6+1}{6}=\dfrac{9}{4}\times \dfrac{7}{6}=\dfrac{63}{24}=\dfrac{21}{8}$

5 step:

$\dfrac{9}{4}+32-\dfrac{21}{8}+1.65=(32+1.65)+\left(\dfrac{9}{4}-\dfrac{21}{8}\right)=33.65+\dfrac{9\cdot 2-21}{8}=33.65-\dfrac{3}{8}=33.65-0.375=33.275$

6 0

3 years ago