Answer:
The required ratio is 2:1
Step-by-step explanation:
Consider the provided information.
The surface area of a six sides cube, is 6s²
It is given that the sides are 3 mm long.
Therefore, the surface area is:
Hence, the surface area is 54 mm²
The volume of cube is
Therefore, the volume is:
We need to find the ratio of surface-area-to-volume
Therefore the required ratio is:
Hence, the required ratio is 2:1
Answer:
x=6
Step-by-step explanation:
if Q is the midpoint, then its halfway. That means PR=PQ+QR
which means PQ=QR
so...32=3x+14
subtract 14 from both sides
18=3x
divide both sides by 3
18/3=6
3x/3=x
so
x=6
Answer: the list of roots is {-4, 2, -3+2i, -3-2i}
Use the quadratic formula to get the roots of the two separate terms in brackets:
x^2+6x+8=0 has solutions: -4 and 2
x^2+6x+13=0 has solutions: -3+2i and -3-2i
Answer:
224
Step-by-step explanation:
<u>Base:</u>
A = Bh
A = 8(8) = 64
<u>Sides:</u>
A = 1/2 Bh
A = 1/2 8(10)
A = 40
<u>Then you do 40(4) because there are 4 sides:</u>
40 (4) = 160
<u>Then you add up the base and the sides:</u>
160 + 64 = 224
(I think this is the right answer)
No, a set is only a subset of another set if it only contains elements contained in the original set.
3 isn't an element of {1,2,4,5,6}, so {3} isn't a subset of {1,2,4,5,6}.