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2 years ago

14

I) state the

1 answer:

topjm [15]2 years ago

6 0

Answer:

i am beginner hep me plz

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If (cos)x= 1/2 what is sin(x) and tan(x)? Explain your steps in complete sentences.

Natasha_Volkova [10]

The correct answers are:
1) sin(x) = $\frac{ \sqrt{3} }{2}$
2) tan(x) = $\sqrt{3}$

Explanation:
Given:
$cos(x) = \frac{1}{2}$

Step 1:
Since, according to the Trigonometric identity:
$sin^2(x) + cos^2(x) = 1$ -- (1)

Step 2:
Plug in the value of cos(x) in equation (1):
$sin^2(x) + ( \frac{1}{2} )^2 = 1 \\ sin^2(x) + \frac{1}{4} = 1 \\ sin^2(x) = \frac{3}{4}$

Step 3:
Take square-root on both sides:
$\sqrt{sin^2(x)} = \sqrt{\frac{3}{4}}$

sin(x) = $\frac{ \sqrt{3} }{2}$

Now to find the tan(x), we would use the following formula:

tan(x) = $\frac{sin(x)}{cos(x)}$ --- (2)

Plug in the values of sin(x) and cos(x) in equation (2):
tan(x) = $\frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{2} }$

Hence tan(x) = $\sqrt{3}$

6 0

2 years ago

Read 2 more answers

The field inside a running track is made up of a rectangle that is 84.39 m long and 73 m wide, together with a half-circle at ea

ioda

Answer:

The distance around the inside is 199.44 m.

Step-by-step explanation:

Given that,

Length = 84.39 m

Width = 9.76 m

Suppose, all the way around and 73 m wide.

We know that,

Perimeter of half circle is

$perimeter = \pi r$

We need to calculate the inner radius of the circle

Using formula of radius

$r=\dfrac{D}{2}$

Put the value into the formula

$r=\dfrac{9.76}{2}$

$r=4.88\ m$

We need to calculate the distance around the inside

Using formula of distance

Distance around the inside= two inner perimeter of the circle+two length of rectangle

$D=2\pi r+2l$

Put the value into the formula

$D=2\pi\times4.88+2\times84.39$

$D=199.44\ m$

Hence, The distance around the inside is 199.44 m.

6 0

3 years ago

A bag contains 816 White market 14 red marbles and 10 Green marbles a marble is drawn at random from the bag what is the probabi

AveGali [126]

the answer that it is not going to be white is 1

3 0

2 years ago

Will mark brainiest pls just lmk

aksik [14]

Answer:

If asking for the distance, the answer would be C.

4 0

2 years ago

Read 2 more answers

What is the maximum height of of Anna's golf ball? The equation is y=x−0.04x2.

elena-s [515]

Given:

The height of a golf ball is represented by the equation:

$y=x-0.04x^2$

To find:

The maximum height of of Anna's golf ball.

Solution:

We have,

$y=x-0.04x^2$

Differentiate with respect to x.

$y'=1-0.04(2x)$

$y'=1-0.08x$

For critical values, $y'=0$ .

$1-0.08x=0$

$-0.08x=-1$

$x=\dfrac{-1}{-0.08}$

$x=12.5$

Differentiate y' with respect to x.

$y''=(0)-0.08(1)$

$y''=-0.08$

Since double derivative is negative, the function is maximum at $x=12.5$ .

Substitute $x=12.5$ in the given equation to get the maximum height.

$y=(12.5)-0.04(12.5)^2$

$y=12.5-0.04(156.25)$

$y=12.5-6.25$

$y=6.25$

Therefore, the maximum height of of Anna's golf ball is 6.25 units.

7 0

2 years ago