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Gwar [14]
3 years ago
8

The Sequence of -2,-14,-26,-38

Mathematics
1 answer:
icang [17]3 years ago
5 0

Answer:

-12

Step-by-step explanation:

Since we can subtract 12 from -2 and get -14, we might try subtracting 12.

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The temperature in Quebec City was 5°C at 4 pm. By midnight, the temperature dropped 15 degrees.
TEA [102]

Answer:

Point A.

Step-by-step explanation:

We know that the temperature dropped 15 degrees, and that it was initially of 5°C. So, by midnight, the temperature will be of -10°C (5-15=-10).

We also know that the distance between points is of 5°C. So, the point that we have to mark is point A, which represents -10°C.

7 0
3 years ago
Read 2 more answers
3X - 4 = 17 flowchart ​
jok3333 [9.3K]

3x=21

x=21/3

x=7

hope it helps

8 0
3 years ago
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Please help... 12! - 9^3
Naily [24]

Answer:

-729

Step-by-step explanation:

-9^3 = -9 x (-9) x (-9) =

          -9x(-9) = 81

                   81x(-9)=-729

4 0
3 years ago
Read 2 more answers
Find the value of the variable such that: the value of 5−a is 20 greater than the value of 6a−1
vovangra [49]

Answer:

-2

Step-by-step explanation:

(5 - a) = 20 + (6a -1) . . . . . 5-a is 20 greater than 6a-1

5 = 7a +19 . . . . . . . . . . . . . add a, collect terms

-14 = 7a . . . . . . . . . . . . . . . subtract 19

-2 = a . . . . . . . . . . . . . . . . divide by 7

The value of the variable is -2.

_____

<u>Check</u>

5 - (-2) = 7

6(-2) -1 = -13

7 is 20 greater than -13, so the answer checks OK.

4 0
3 years ago
.
Sunny_sXe [5.5K]

The solutions of the equations are -1.3 and -7.7

Step-by-step explanation:

The quadratic formula of solving the quadratic equation

ax² + bx + c = 0, where a, b and c are constant is:

x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}

To solve the quadratic equation by using the quadratic formula

1. Find the values of a , b and c from the equation

2. Substitute the values of a , b and c in the quadratic formula

3. Find the two values of x

∵ x² + 9x + 10 = 0

∴ a = 1 , b = 9 and c = 10

∵ x=\frac{-9+\sqrt{(9)^{2}-4(1)(10)}}{2(1)}

∴ x=\frac{-9+\sqrt{81-40}}{2}

∴ x=\frac{-9+\sqrt{41}}{2}

∴ x = -1.3

∵ x=\frac{-9-\sqrt{(9)^{2}-4(1)(10)}}{2(1)}

∴ x=\frac{-9-\sqrt{81-40}}{2}

∴ x=\frac{-9-\sqrt{41}}{2}

∴ x = -7.7

The solutions of the equations are -1.3 and -7.7

Learn more:

You can learn more about quadratic equation in brainly.com/question/8196933

#LearnwithBrainly

6 0
3 years ago
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