Question

1. In a certain course, grades are based on three tests worth 100 points each, three quizzes worth 50 points each, and a final exam worth 200 points. A student has test grades of 91, 82, and 88, and quiz grades of 50, 42, and 42. What is the lowest percent the student can get on the final and still earn an A (90% or more of the total points) in the course

Answer 1

Answer:

95%

Step-by-step explanation:

Three tests worth 100 points each = 3 X 100 = 300 points

Three quizzes worth 50 points each = 3 X 50 =150 points

Final exam worth 200 points

Total Obtainable Points=300+150+200=650

Total of test grades obtained (91, 82, and 88)=91+82+88=261

Total of quiz grades (50, 42, and 42) obtained = 50+42+42=134

Let x be the exam score for the student to obtain 90%

Therefore:

$\frac{261+134+x}{650} X 100 \geq 90\\\frac{100(395+x)}{650} \geq 90\\39500+100x \geq 90X650\\39500+100x \geq 58500\\100x \geq 58500-39500\\100x \geq19000\\x \geq190$

The lowest score a student can score is 190.

Expressed as a percentage of 200,

$\frac{190}{200}X100=95$ per cent

The student must score a minimum of 95% in order to make an A.