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Elanso [62]
3 years ago
15

113 + taxes ________________​

Mathematics
1 answer:
natita [175]3 years ago
6 0
If the Taxes % is 8.25 the it would be a total of $122.32
Only the taxes of 113 is 9.32
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Dr. Green finds a note from another scientist. It says how many boxes of bug nets they should bring, but there is a smudge over
Marizza181 [45]

Answer:

The correct answer is the number in the note is 80 and the first digit is 8.

Step-by-step explanation:

Dr. Green finds a note from another scientist. It says how many boxes of bug nets they should bring, but there is a smudge over the first digit of the number.

Number of nets that they must bring is 320.

Each box contains 4 nets.

There number of boxes necessary to be brought is given by \frac{320}{4} = 80.

Therefore the missing digit of number the number in the note is 8.

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3 years ago
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Rasek [7]

Answer:

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Step-by-step explanation:

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What is the perimeter of a trapezoid having side lengths of 20 ft, 20 ft, 26 ft and 18 ft?
Irina18 [472]
The perimeter would be 84
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Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

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3 years ago
A machine paints 158 toy planes in 45 minutes. find the unit rate per hour.
Stella [2.4K]
3.51/1 hope that helps
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