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Kay [80]
3 years ago
9

What is the perimeter of a trapezoid having side lengths of 20 ft, 20 ft, 26 ft and 18 ft?

Mathematics
1 answer:
Irina18 [472]3 years ago
8 0
The perimeter would be 84
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How many litters of apple syrup and water did she use in the ratio of 2:3 and made 1800 ml of such fruit juice
sp2606 [1]

Answer:

720 mL ; 1080 ml

Step-by-step explanation:

Givenn:

Apple syrup : water = 2 : 3

Fruit juice volume made using the ratio above = 1800 ml

Sum of ratio = 2 + 3 = 5

Litres of Apple syrup :

(Syrup ratio / total) * total volume of fruit

(2 / 5) * 1800

= 0.4 * 1800

= 720 ml

Litres of water :

(water ratio / total) * total volume of fruit

(3 / 5) * 1800

= 0.6 * 1800

= 1080 ml

5 0
3 years ago
What is 0.5 repeating as a fraction in simplest form
Solnce55 [7]

Answer:

5/9

Step-by-step explanation:

Start be letting x = 0.555...

Our original equation is:

x = 0.555...

There is only one digit repeating, the 5, so we multiply both sides of that equation by 10 and write it above the original equation.

10x = 5.555...

   x = 0.555...

Now we subtract the second equation from the first equation as written above.

9x = 5

Divide both sides by 9.

x = 5/9

0.555... = 5/9

6 0
3 years ago
The “new look” of the cereal boxes has a length that is three more than two times the width, x, and a height that is one more th
jok3333 [9.3K]

The first option is correct. For the following question, the simplified expression for the volume is 8x3 + 14x2 + 3x.

5 0
3 years ago
Read 2 more answers
How do you solve this
UNO [17]
7 divided by 1 is 7 so you would do long division
5 0
3 years ago
Question Help Suppose that the lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a
koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So \mu = 5656, \sigma = 333.3

(a) What proportion of light bulbs will last more than 6262 ​hours?

The pvalue of the z-score of X = 6262 is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.

Z = \frac{X - \mu}{\sigma}

Z = \frac{6262 - 5656}{333.3}

Z = 1.82

Z = 1.81 has a pvalue of .96562. This means that 96.562% of the light bulbs are going to last less than 6262 hours. So

P = 100% - 96.562% = 3.438% of the light bulbs will last more than 6262 hours.

​(b) What proportion of light bulbs will last 5252 hours or​ less?

This is the pvalue of the zscore of X = 5252

Z = \frac{X - \mu}{\sigma}

Z = \frac{5252- 5656}{333.3}

Z = -1.21

Z = -1.21 has a pvalue of .1131. This means that 11.31% of the light bulbs will last 5252 hours or less.

(c) What proportion of light bulbs will last between 5858 and 6262 ​hours?

This is the pvalue of the zscore of X = 6262 subtracted by the pvalue of the zscore X = 5858

For X = 6262, we have that Z = 1.81 with a pvalue of .96562.

For X = 5858

Z = \frac{X - \mu}{\sigma}

Z = \frac{5858- 5656}{333.3}

Z = 0.61

Z = 0.61 has a pvalue of .72907.

So, the proportion of light bulbs that will last between 5858 and 6262 hours is

P = .96562 - .72907 = .23655

23.655% of the light bulbs are going to last between 5858 and 6262 hours.

​(d) What is the probability that a randomly selected light bulb lasts less than 4646 ​hours?

This is the pvalue of the zscore of X = 4646

Z = \frac{X - \mu}{\sigma}

Z = \frac{4646- 5656}{333.3}

Z = -3.03

Z = -3.03 has a pvalue of .0012. This means that 0.12% of the light bulbs will last 4646 hours or less.

5 0
3 years ago
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