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3 years ago

14

Round 1,384 to the nearest thousand and round 2,332 to the nearest hundred

2 answers:

Anna11 [10]3 years ago

7 0

1,384 rounded to the nearest thousand would be 1,000 because when you look at the hundreds place, there is a 3 and the rule is, if it’s under 5 round down but if it’s over 5 (or if it is 5) you round up.
2,332 rounded to the nearest hundred would be 2,300 because once again there was a number less than 5 before it so we rounded down.
I hope this helped! Have a wonderful day! :-)

monitta3 years ago

6 0

1,348 is 1000 and 2,332 is 2,300

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The ratio of the measures of three angles is 3:8:9. find the measure of each angle of the triangle.

MAXImum [283]

To solve this problem you must apply the proccedure shown below:

1. You have that the ratio of the measures of the three angles is $3:8:9$

2. The sum of the interior angle of a triangle is $180degrees$

3. Let's say that the measure of each angle is $x$ multiplied by the ratio. Therefore, you can write the following equation and solve for $x$ :

$3x+8x+9x=180\\ x=9$

4. Therefore, the measure of each angle is:

$3(9)=27degrees\\ 8(9)=72degrees\\ 9(9)=81degrees$

The answer is: $27degrees, 72degrees,81degrees$

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3 years ago

What is the word form for the number 2,059

gulaghasi [49]

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2 years ago

Read 2 more answers

Write as an equation: Sara spent $2 more than Lauren, and together they spent $19.

kupik [55]

Answer:

Equations:

a + b = 19

a = b + 2

a = Money that spent Laura

b = Money that spent Laureen

then:

(b+2) + b = 19

2b + 2 = 19

2b = 19-2

2b = 17

b = 17/2

b = 8.5

a = b + 2

a = 8.5 + 2

a = 10.5

Check:

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3 years ago

The linear relationship represented by the table has an initial value of 88 and a rate of change -6. Complete the table.

Nimfa-mama [501]

(2,88)
(6,64)
(9,46)
(15,10)
first find y=mx+b
88=-6(2)+b
b=100
y=-6x+100
then plug for y and solve for x or vise versa.
Hopes this loves

8 0

3 years ago

Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

<u>Solution:</u>

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

3 years ago