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slavikrds [6]
3 years ago
13

The exponential model A=429e 0.024t describes the​ population, A, of a country in​ millions, t years after 2003. Use the model t

o determine when the population of the country will be 559 million.
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
7 0

Answer:

Year 2,590

Step-by-step explanation:

In this question, we are asked to calculate the year at which the population of a country will be a certain amount given the exponential equation through which the equation proceeds.

Let’s rewrite the exponential function;

A = 429e^0.024t

Now here, our A is 559,000,000

t is unknown

Let’s substitute this value of A in the exponential equation;

559,000,000 = 429 * e^0.024t

559,000,000/429 = e^0.024t

1,303,030.303030303 = e^0.024t

Let’s take the logarithm of both sides to base e, we have;

ln(1,303,030.303030303) = ln(e^0.024t)

14.08 = 0.024t

t = 14.08/0.024

t = 587 years

Now, we add this to year 2003 and this gives year 2590

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3 years ago
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Multiply 4/5 by the reciprocal of −2/10.
Svetach [21]

Answer:

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Cancelling the numbers

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Step-by-step explanation:

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Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

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How do you this question?
Svetlanka [38]

Answer:

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Step-by-step explanation:


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3 years ago
If f(x)=-8x+8 and g(x) = sqrt x-9 what is (f•g)(18)
Serggg [28]

Answer:

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Step-by-step explanation:

f(x)=-8x+8 and g(x) = sqrt x-9

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g(18)=sqrt(18-9)=sqrt9=3

f(3)=-24+8=-16

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