Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Answer:
y=3 x=1
Step-by-step explanation:
Let's solve your equation step-by-step.
2x+1=4x−1
Step 1: Subtract 4x from both sides.
2x+1−4x=4x−1−4x
−2x+1=−1
Step 2: Subtract 1 from both sides.
−2x+1−1=−1−1
−2x=−2
Step 3: Divide both sides by -2.
−2x
−2
=
−2
−2
x=1
then
y=(2)(1)+1
Answer:
y=3
The mean is the average of a given data set and can be obtained by taking the sum of all numbers and dividing that by the amount of numbers in the data set.
58 + 43 + 33 + 69 + 41 + 74 = 318
There are 6 numbers in the data set.
318 / 6 = 53
The slope will point downwards towards the left as the coefficient of x is negative and it the negative applies to the numerator
