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Anna007 [38]
3 years ago
12

Please answer the 3rd Question please answer it fast............I WILL MARK YOU AS THE BRANLIEST.................

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

since LM=LN there values are same which is given as 5.5 cm and MN =7cm

now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs  will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!

Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.

<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>

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3 years ago
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Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

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a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

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5 0
3 years ago
Find the slope of the line that passes through (-53, -2) and (-54, 91).
cricket20 [7]

Answer:

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x2=-54. y2=91

slopes= y2-y1

---------

x2-x1

91-(-2)

-----------------

= -54-(-53)

91+2

= ----------

-54+53

= 93

-------

-1

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3 years ago
What is 150% of 200. Show work. ASAP
zalisa [80]
150 % of 200

150 / 100 =  1.5

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