Question

A) Complete the table of values for y = x2 + x - 4

Answer 1

Answer:

The values of y for each value of x are:

$x = -3, y =2$

$x = -2\: , y =-2$

$x = -1\: , y =-4$.

$x = 0\: , y =-4$

$x = 1\: , y = -2$.

$x = 2\: , y =2$

$x = 3\: , y = 8$

Step-by-step explanation:

We have all the values of x, they are from -3 to 3 passing for 0.

Now, we know that y is a quadratic function (y=x²+x+4)

Therefore, we just need to put each value of x into the quadratic equation to find each y value.

When:

$x = -3, y = (-3)^2+(-3)-4=2$

$x = -3\: , y = 2$

We can do this for all values of x, so we will have:

$x = -2\: , y = (-2)^2+(-2)-4=-2$

$x = -1\: , y = (-1)^2+(-1)-4=-4$.

$x = 0\: , y = (0)^2+(0)-4=-4$

$x = 1\: , y = (1)^2+(1)-4=-2$.

$x = 2\: , y = (2)^2+(2)-4=2$

$x = 3\: , y = (3)^2+(3)-4=8$

I hope it helps you!