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Cerrena [4.2K]
3 years ago
10

A) Complete the table of values for y = x2 + x - 4

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

The values of y for each value of x are:

x = -3, y =2

x = -2\: , y =-2

x = -1\: , y =-4.

x = 0\: , y =-4

x = 1\: , y = -2.

x = 2\: , y =2

x = 3\: , y = 8

Step-by-step explanation:

We have all the values of x, they are from -3 to 3 passing for 0.

Now, we know that y is a quadratic function (y=x²+x+4)

Therefore, we just need to put each value of x into the quadratic equation to find each y value.

When:

x = -3, y = (-3)^2+(-3)-4=2

x = -3\: , y = 2

We can do this for all values of x, so we will have:

x = -2\: , y = (-2)^2+(-2)-4=-2

x = -1\: , y = (-1)^2+(-1)-4=-4.

x = 0\: , y = (0)^2+(0)-4=-4

x = 1\: , y = (1)^2+(1)-4=-2.

x = 2\: , y = (2)^2+(2)-4=2

x = 3\: , y = (3)^2+(3)-4=8

I hope it helps you!

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Help me plzzzzzzzzz!!!!!!!!!!!!!!!!!!
Anvisha [2.4K]

Answer: ( 12 , 9 )

Step-by-step explanation:

The formula for finding the coordinate of points when a line is externally divided in a given ratio is given by :

x = \frac{p x_{2}+q x_{1}}{p+q}

y = \frac{p y_{2}+q y_{1}}{p+q}

From the question

x_{1} = 2

x_{2} = ?

x = 4

y_{1} = -1

y_{2} = ?

y = 1

p = 1

q = 4

substituting the values into the formula ,we have

x = \frac{p x_{2}+q x_{1}}{p+q}

4 = \frac{1(x_{2})+4(2) }{1+4}

4 = \frac{x_{2}+8}{5}

x_{2} + 8 = 20

x_{2} = 12

Also

y = \frac{p y_{2}+q y_{1}}{p+q}

1 = \frac{y_{2}+4(-1)}{5}

y_{2} - 4 = 5

y_{2} = 9

Therefore , the end of the stencil is located at point ( 12 , 9 )

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3 years ago
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Consider this algebraic expression:     –3x + x + 5 Use the algebra tiles to model the expression.
luda_lava [24]

For this case, we have the following expression:

-3x + x + 5

We simplify the expression:

If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that -3x + x = -2x

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Simplify: (3n2 +9+5n4 – 3n)+(-9n* - 7 -5n?)
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Answer:

3n^2+9+5n^4+55n

Step-by-step explanation:

Steps

$\left(3n^2+9+5n^4-3n\right)+\left(-9n\left(-7\right)-5n\right)$

$\mathrm{Remove\:parentheses}:\quad\left(a\right)=a,\:-\left(-a\right)=a$

$=3n^2+9+5n^4-3n+9n\cdot\:7-5n$

$\mathrm{Add\:similar\:elements:}\:-3n-5n=-8n$

$=3n^2+9+5n^4-8n+9\cdot\:7n$

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$\mathrm{Add\:similar\:elements:}\:-8n+63n=55n$

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