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Darina [25.2K]
3 years ago
13

The weight of a nickel is 80% of a quarter. If a nickel weighs 5 grams how much does a quarter weigh?

Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

Weight of a quarter  = 6.25 grams

Weight of a dime  = 2.5 grams

Step-by-step explanation:

The weight of a nickel is  80%

The weight of a quarter  or the weight of a nickel is 5 grams or weight of a quarter =50.8 = 6.25 grams

Weight of a dime = 50% = 12 (weight of nickel) = 52 = 2.5 grams

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What is the value of the expression below?<br> (-8)^4/3<br> A. 32<br> B. 16<br> C. -16<br> D. 3
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-16

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What are benchmark angles?
Komok [63]
Any angle that is bent at 45 degree, 90 degree,180 degree are called benchmark angles. Obtuse angle, Acute angle, Right angle, Straight angle are called benchmark angles

4 0
3 years ago
The admissions office of a private university released the following data for the preceding academic year: From a pool of 3900 m
Finger [1]

Answer:

a. 0.09 or 9%

b. 0.324 or 32.4%

c. 0.0972 or 9.72%

Step-by-step explanation:

Male applicants = 3900

Female applicants = 3600

Total applicants = 7,500

Proportion of male applicants (m) = 0.52

Proportion of female applicants (f) = 0.48

a. The probability that a random male applicant is accepted and enrolls is given by the probability of a male student being accepted multiplied by the probability of a male student enrolling:

P(a) = 0.30*0.30=0.09=9\%

b. The probability that a random student is accepted is given by the probability of a male applicant being accepted added to the probability of a female applicant being accepted

P(b) = m*0.30+f*0.35\\P(b) = 0.52*0.30+0.48*0.35\\P(b) = 0.324=32.4\%

c. The probability that a random student is accepted and enrolls is given by the probability of a male applicant being accepted and enrolling added to the probability of a female applicant being accepted and enrolling

P(b) = m*0.30*0.30+f*0.35*0.30\\P(b) = 0.52*0.30*0.30+0.48*0.35*0.30\\P(b) = 0.0972=9.72\%

7 0
3 years ago
What is the perimeter (in inches) of a television screen that measures 24 1/2 in. by 40 in.?
Bess [88]

The perimeter of the television screen (in inches) is 129 inches.

Given that a television screen in the shape of a rectangle has a length of    40 inches and breadth \frac{49}{2} inches.

Perimeter of rectangle=2(length of rectangle+ bredth of rectangle)

Here the TV screen is the shape of rectangle

Therefore Perimeter of TV screen=perimeter of rectangle

Given the the length of TV screen=40 inches

The bredth of the TV screen= \frac{49}{2} inches.

Perimeter of TV screen=2(40 inches + \frac{49}{2} inches)

Perimeter of TV screen=(80+49) inches

Perimeter of TV screen= 129 inches

Therefore,The perimeter of the television screen (in inches) is 129 inches.

Learn more about perimeter here:

brainly.com/question/6465134

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4 0
1 year ago
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