Answer:
The new sum have degree = 5
The maximum number of terms of the sum is 6, but it could be less.
Step-by-step explanation:
Given :
Raj writes a polynomial expression in standard form using one variable, a, that has 4 terms and is degree 5.
Let the polynomial: 
Next, Nicole writes a polynomial expression in standard form using one variable, a, that has 3 terms and is degree 2.
The polynomial is: 
Now, adding both polynomials we have:
→ The new sum have degree = 5
→ The maximum number of terms of the sum is 6, but it could be less.
Answer:
Step-by-step explanation:
given equation
subtracting 17 from both sides
the solution for quadratic equation
is given by
x = 
________________________________
in our problem
a = 1
b = 2
c = -16
thus value of x is
Our repeating decimal would be= 0.5555….
Let’s give 0.5555….. repeating decimal a variable of x:
x= 0.5555…. or 0.5(move 1 point to the right)
So ,10x = 5.5555 or 5.5
Now, Let’s do subtraction:
10x = 5.5555… or 5.5
<u>- x = 0.5555… or 0.5</u>
9x
= 5.0 or 5.0
To get a fraction, provide a denominator the same with the numerator of variable x which is 9. Then divide the difference:
<span><u>9x</u> = <u>5.0</u>
9 9</span>
<span>
<span><span>
<span>
<span>Therefore, x = <u>5
</u> 9</span>
</span>
</span>
</span></span>
Answer:
y ≥−3
Step-by-step explanation:
1 By inspecting the graph, the range is:
y\ge -3y≥−3
Done
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
