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It's the third choice. Since the symbol is not greater than or equal to -3 so it must got left..
If the numbers were 50 divided by 12 this is how you would answer it. And I showed the reduced answer too.
3x^2 -2root(6)x + 2 = 0
(root(3)x)^2 -2[root(3)x]root(2)+ (root(2))^2 = 0
let a = root(3)x and b = root(2)
a^2 -2ab + b^2 = 0
(a - b)^2 = 0
by the null factor rule,
a - b = 0
sub back in a and b
root(3)x = root(2)
x = root(3)/root(3)