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timofeeve [1]
3 years ago
5

PLEASE HELP ASAP ON TIMED QUIZ

Physics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

It is C and 100 percent sure about it

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The attractive force between two objects that
elena-s [515]

Answer:

The answer is gravity

Explanation: Hope this helps:)

8 0
3 years ago
Read 2 more answers
John pushes his brother Danny on a skateboard. John applies a force of 29 N and Danny's acceleration is 0.4 m/s^2
erastova [34]

The combined mass of Danny+skateboard is 72.5 kg

Explanation:

We can solve the problem by using Newton's second law of motion:

F=ma

where:

F is the net force applied on Danny and the skateboard

m is the mass of Danny+skateboard

a is the acceleration

Here we have the following data:

F = 29 N is the force applied

a=0.4 m/s^2 is the acceleration of Danny and the skateboard

Solving for m, we find their combined mass:

m=\frac{F}{a}=\frac{29}{0.4}=72.5 kg

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The linear speed of a passenger on the
Marina86 [1]

Answer:

a) The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 90^{\circ}.

b) Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 270^{\circ}.

c) The Ferris wheel takes 14.646 seconds to make a revolution.

Explanation:

a) An object that rotates at constant angular velocity reports a centripetal acceleration and no tangential acceleration. When passenger passes through the lowest point in her circular motion, centripetal acceleration goes up to the center.

In addition, centripetal acceleration is determined by the following expression:

a_{R} = \frac{v^{2}}{R} (Eq. 1)

Where:

a_{R} - Centripetal acceleration, measured in meters per square second.

v - Linear speed, measured in meters per second.

R - Radius of the Ferris wheel, measured in meters.

If we know that v = 6\,\frac{m}{s} and R = 14\,m, the magnitude of radial acceleration is:

a_{R} = \frac{\left(6\,\frac{m}{s} \right)^{2}}{14\,m}

a_{R} = 2.571\,\frac{m}{s^{2}}

The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 90^{\circ}.

b) In the highest point the magnitude of radial acceleration is the same but direction is the opposed to that at lowest point. That is, centripetal acceleration goes down to the center.

Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 270^{\circ}.

c) At first we need to calculate the angular velocity of the Ferris wheel (\omega), measured in radians per second, by using the following expression:

\omega = \frac{v}{R} (Eq. 2)

If we know that v = 6\,\frac{m}{s} and R = 14\,m, then the angular velocity of the Ferris wheel is:

\omega = \frac{6\,\frac{m}{s} }{14\,m}

\omega = 0.429\,\frac{rad}{s}

Now we proceed to obtain the period of the Ferris wheel (T), measured in seconds, which is the time needed by that wheel to make on revolution:

T = \frac{2\pi}{\omega} (Eq. 3)

Where \omega is the angular velocity of the Ferris wheel, measured in radians per second.

If we get that \omega = 0.429\,\frac{rad}{s}, then:

T = \frac{2\pi}{0.429\,\frac{rad}{s} }

T = 14.646\,s

The Ferris wheel takes 14.646 seconds to make a revolution.

8 0
3 years ago
A bus travels North for 10 miles then turns around and
Lesechka [4]
The displacement of the bus is 6.25 miles.
4 0
4 years ago
A car traveling west in a straight line on a highway decreases its speed from 30.0 meters per second to 23.0 meters per second i
pychu [463]
Acceleration, a =  (v - u) / t

Initial Velocity, u = 30 m/s
Final Velocity, v  =  23 m/s
time                 t  =  2.00 seconds

a = (23 - 30) / 2
a = -7 / 2 = -3.5 m/s2

So the acceleration  is negative, which means it is a deceleration of 3.5 m/s2.
8 0
3 years ago
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