PLEASE HELP ASAP ON TIMED QUIZ

Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier. It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.

1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .

Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach 3,000,000 m/s ?

   (3,000,000 m/s) / (9.8 m/s²) = 306,122 seconds .
   (That's 5,102 minutes.)
(That's 85 hours.)
   (That's 3.54 days.)

Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s

Distance = (average speed) x (time)

   = (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters

   = 459 million kilometers

   That's like from Earth
      to    Sun
       to    Earth
          to Sun.

4 0

3 years ago

What are the basic ethical guidelines for psychological research?

Sergeeva-Olga [200]

Five principles for research ethics

Discuss intellectual property frankly

Be conscious of multiple roles

Follow informed-consent rules.

Respect confidentiality and privacy.

Tap into ethics resources.

3 0

3 years ago

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed

mafiozo [28]

Answer:

0.6375 m/s

Explanation:

Let x be the distance of the man from the building

from the figure attached

initially the value of x=12

Given:

$\frac{dx}{dt}=-1.7m/s$

where the negative sign depicts that the distance of the man from the building is decreasing.

Now, Let The length of the shadow be = y

we have to calculate $\frac{dy}{dt}$ when x=4

from the similar triangles

we have,

$\frac{2}{12-x}=\frac{y}{12}$

or

$y=\frac{24}{12-x}$

Differentiating with respect to time 't' we get

$\frac{dy}{dt}=-\frac{24}{12-x}^2\frac{-dx}{dt}$

or

$\frac{dy}{dt}=\frac{24}{12-x}^2\frac{dx}{dt}$

Now for x = 4, and $\frac{dx}{dt}=-1.7m/s$ we have,

$\frac{dy}{dt}=\frac{24}{12-4}^2\times (-1.7)$

or

$\frac{dy}{dt}=-0.6375m/s$

<u>here, the negative sign depicts the decrease in length and in the question it is asked the decreasing rate thus, the answer is </u><u>0.6375m/s</u>

4 0

4 years ago