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serg [7]
4 years ago
9

What happens to light as it moves at an angle into a medium that has a lower index of refraction?

Physics
1 answer:
Aleks04 [339]4 years ago
6 0

Answer:

It speeds up, and the angle increases.

Explanation:

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What energy comes from a rining bell
Harrizon [31]

Answer: Sound Energy

Sound Energy

Explanation:The vibrations produced by the ringing bell causes waves of pressure that travel or propagate through the medium that is air. Sound energy is a form of mechanical energy that is generally associated with the motion and position of the ringing bell.

7 0
3 years ago
Newton's third law says that for every force there is an equal reaction force in the opposite direction. what does this imply ab
stealth61 [152]

This imply that the force applied by the gravity of the earth on the person, is equal to the force applied by the person on the earth.

According to the Newton's third law, for every force there is an equal reaction force, in the case of person standing on the earth, the gravity of the earth pulls the person by the same magnitude as the force applied by the person on the earth (which is equal to the weight of the person)..

7 0
3 years ago
You are writing a science report and want to find accurate trustworthy information. Which would be the best resource?
fgiga [73]
<span>an encyclopedia

Happy studying!</span>
8 0
4 years ago
Read 2 more answers
Explain newton 2nd law ???<br><br>​
shusha [124]

Explanation:

Newton's second law simply says that the net force on an object is equal to the object's mass times its acceleration.

∑F = ma

For example, think of a game of tug-of-war, in which two teams pull on a rope in opposite directions.

If the forces are equal (balanced), then the net force is 0 N, so Newton's second law tells us that the rope's acceleration is 0 m/s².

If the forces are not equal (unbalanced), then the net force is not 0 N, and the rope will accelerate in the direction of the net force.

7 0
4 years ago
A slit 0.240mm wide is illuminated by parallel light rays with a wavelength 600nm . The diffraction pattern is observed on a scr
taurus [48]

To solve this exercise, it is necessary to apply the concepts on the principle of superposition, specifically on constructive interference,

Constructive interference (light spot) is defined by

dsin\theta=m\lambda

Where,

m = The integer m is called the interference order and is the number of wavelengths by which the two paths differ.

\lambda = wavelenght

d = Distance

For smaller angles sin\theta = tan\theta,

d tan\theta = m \lambda

From the trigonometric properties it is understood that so the is - in this case - the length measured vertically by reason of distance, that is

d*\frac{y}{L} = m\lambda

Re-arrange to find y,

y = \frac{m\lambda L}{d}

Replacing our values

y  = \frac{(1)(600*10^{-9}(3.5m)}{0.240*10^{-3}m}

y = 8.75*10^{-3}m

y = 8.75mm

PART B) To calculate the intensity it is necessary to find the angle between the previously calculated height and distance in order to calculate the phase angle, in other words,

tan\theta' = \frac{y}{L}

tan\theta' = \frac{1/2(8.75*10^{-3})}{3.5}

\tetha = 0.07161\°

Therefore phase angle is

\gamma = \frac{2\pi}{\lambda}sin\theta'

\gamma = \pi

The intensity formula would then be given by,

I = I_0 \frac{sin\frac{\gamma}{2}^2}{\frac{\gamma}{2}}

I = 4.1*10^{-6}(\frac{4}{\pi})

I = 1.66*10^{-6}W/m^2

3 0
3 years ago
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