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tamaranim1 [39]
2 years ago
11

In 1980, the first cd's hit the music stores. that year at a local music store 5,000 cd's were sold. each year after that, cd sa

les at that store increased constantly at a rate of 15,000 per year. Write a linear function for the cd's sold, C, as a function of time, t.
Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
4 0

In the first year of the sale the C.D's sold = 5000.

Now next year there was an increase by 15000

C.D's sold in second year = 5000 + 15000

in third year number of cd's sold = 5000 +15000 + 15000

= 5000 + 15000*2

in fourth year it was : 5000 + 15000 * 2+ 15000 = 5000 + 15000* 3

this means in the t year number of cd's sold = 5000 + ( t-1)* 15000

let us simplify it 5000 + 15000 t - 15000

15000 t - 10000

Answer : 15000t - 10000

crimeas [40]2 years ago
3 0

at first year 5000 compact discs were sold.

and it increased at a rate of 15000 per year in the upcoming year .

we need to linear function which mean if we graph it will get a straight line.

which is in the form of y=mx+b

where y=f(t) which means functions represented in time.

where 15000 is the slope of the equation which is increasing at this rate.

and b is the y intercept which mean from 5000 sales has been increased.

so the linear equation is

f(t)=15000(t)+5000

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In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.
Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

Hence, x value is 12 when y value is 9

3 0
3 years ago
If you sleep 33% of the year, how many months do you spend sleeping?
Oksanka [162]

Answer:

3.96 months

Step-by-step explanation:

12 months in a year

12 * 33%= 3.96 months

4 0
2 years ago
How many solutions?​
jeyben [28]

Answer:A) no solutions

Step-by-step explanation:

1) set both problems equal to each other

2) subtract four from each side

3) subtract 2x from each side

4) 10 does not equal 0

3 0
2 years ago
Read 2 more answers
HELPPP I SUCK AT MATH
e-lub [12.9K]
I think the answer is 6
4 0
3 years ago
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
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