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3 years ago

Hpw does the graph of the function g (x) =5x +1 differ from the graph of f(x) = 5x

Mathematics

1 answer:

solniwko [45]3 years ago

4 0

Answer:

g(x) has a +1 for it's b in y = mx+b, and f(x) has 0 for it's b (b is the y intercept)

Step-by-step explanation:

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The equation tan(55) = 15/b can be used to find the length of line AC.what is the length of line AC round to the nearest 10th 3.

Nadusha1986 [10]

Answer:

10.5 in

Step-by-step explanation:

Given

$tan(55) = \frac{15}{b}$

Required

Find length AC

The question is not detailed enough; so, I'll assume that b represents line AC.

Having said that;

We start by multiplying both sides by b

$tan(55) = \frac{15}{b}$

$b * tan(55) = \frac{15}{b} * b$

$b * tan(55) =15$

Divide both sides by tan(55)

$\frac{b * tan(55)}{tan(55)} = \frac{15}{tan(55)}$

$b = \frac{15}{tan(55)}$

Find tan(55)

$b = \frac{15}{1.42814800674}$

$b = 10.5031130731$

$b = 10.5$ (Approximated)

Length AC is 10.5

7 0

3 years ago

Read 2 more answers

If Trent has 11 quarters and dimes in his pocket, and they have a combined value of 200 cents, how many of each coin does he hav

allsm [11]

Answer:

Trent has 6 quarters and 5 dimes.

Step-by-step explanation:

Consider the provided information.

Let q = Number of quarters

d = Number of dimes.

Trent has 11 quarters and dimes.

$q+d=11$

$q=11-d$

The worth of a quarter is 25 cents.

The worth of a dimes is 10 cents

$25q+10d=200$

Substitute the value of q in above equation.

$25(11-d)+10d=200$

$275-25d+10d=200$

$15d=75$

$d=5$

Substitute the value of d in $q=11-d$

$q=11-5$

$q=6$

Hence, Trent has 6 quarters and 5 dimes.

4 0

3 years ago

Si mi hermano gana 589 pesos diarios si ha trabajado 15 días de este mes ¿cuánto dinero ha ganado?

weeeeeb [17]

Mi hermano ha ganado un dinero devengado de 8835 pesos en 15 días.

En esta pregunta debemos determinar el dinero devengado por un período de 15 días a partir de una tasa diaria constante. Esa cantidad es igual al producto de la tasa diaria constante, en pesos por día, y el número de días trabajados, en días:

$x = 589\,\frac{\$}{dia}\times 15\,dias$