Its A, and both by a factor 1/15
first off, is noteworthy that's the graph of an exponential function, thus the function will be along the lines of g(x) = abˣ , now, what's "a" and "b" values?
well, let's take a peek when x = 0 and x = 1.
![\bf g(x) = ab^x \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 0\\ y = 1 \end{cases}\implies 1=ab^0\implies 1=a(1)\implies \boxed{1=a} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 1\\ y = 4 \end{cases}\implies 4 = ab^1\implies 4=1b^1\implies \boxed{4=b} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill g(x) = 4^x\qquad \qquad \qquad \begin{array}{|c|c|ll} \cline{1-2} x&y\\ \cline{1-2} -2&\frac{1}{4^2}\to \frac{1}{16}\\ -1&\frac{1}{4}\\ 0&1\\ 1&4\\ 2&16\\ \cline{1-2} \end{array}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20g%28x%29%20%3D%20ab%5Ex%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20x%20%3D%200%5C%5C%20y%20%3D%201%20%5Cend%7Bcases%7D%5Cimplies%201%3Dab%5E0%5Cimplies%201%3Da%281%29%5Cimplies%20%5Cboxed%7B1%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20x%20%3D%201%5C%5C%20y%20%3D%204%20%5Cend%7Bcases%7D%5Cimplies%204%20%3D%20ab%5E1%5Cimplies%204%3D1b%5E1%5Cimplies%20%5Cboxed%7B4%3Db%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20g%28x%29%20%3D%204%5Ex%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cll%7D%20%5Ccline%7B1-2%7D%20x%26y%5C%5C%20%5Ccline%7B1-2%7D%20-2%26%5Cfrac%7B1%7D%7B4%5E2%7D%5Cto%20%5Cfrac%7B1%7D%7B16%7D%5C%5C%20-1%26%5Cfrac%7B1%7D%7B4%7D%5C%5C%200%261%5C%5C%201%264%5C%5C%202%2616%5C%5C%20%5Ccline%7B1-2%7D%20%5Cend%7Barray%7D~%5Chfill)
<u>Hope this helped!</u>
<u>First Row</u>
6
5
(this one is already done)
<u>Second Row</u>
4
5
6
11
Answer:
The length of the chord is 16 cm
Step-by-step explanation:
Mathematically, a line from the center of the circle to a chord divides the chord into 2 equal portions
From the first part of the question, we can get the radius of the circle
The radius form the hypotenuse, the two-portions of the chord (12/2 = 6 cm) and the distance from the center to the chord forms the other side of the triangle
Thus, by Pythagoras’ theorem; the square of the hypotenuse equals the sum of the squares of the two other sides
Thus,
r^2 = 8^2 + 6^2
r^2= 64 + 36
r^2 = 100
r = 10 cm
Now, we want to get a chord length which is 6 cm away from the circle center
let the half-portion that forms the right triangle be c
Using Pythagoras’ theorem;
10^2 = 6^2 + c^2
c^2 = 100-36
c^2 = 64
c = 8
The full
length of the chord is 2 * 8 = 16 cm
I hope this helps you
x=4 q (4)=8.4-7
q (4)=32-7
q (4)=25
