Answer:
2 bc cos A
Step-by-step explanation:
Cosine rule
The car is speeding at a rate of 33.3mph
<h3>Speed and distance of an object</h3>
If a certain car going 60 mph can stop in 180 ft, then we can express this as:
To determine the speed for a car traveling at 100ft, we will have:
Take the ratio of the expression
60/x = 180/100
180x = 6000
x = 33.3mph
Hence the car is speeding at a rate of 33.3mph
learn more on speed here: brainly.com/question/4931057
<span>let x = the original no. of students
then
(x+10) = the actual no. that went on the trip
:
= the original cost per student
and
= the actual cost
:
Original cost - actual cost = $12.50
- = 12.50
multiply equation by x(x+10)
x(x+10)* - x(x+10)* = 12.50x(x+10)
Cancel the denominators
1500(x+10) - 1500x = 12.5x(x+10)
1500x + 15000 - 1500x = 12.5x^2 + 125x
Combine on the right to form a quadratic equation
0 = 12.5x^2 + 125x - 15000
Simplify, divide equation by 12.5
x^2 + 10x - 1200 = 0
You can use the quadratic formula; a=1; b=10; c=-1200, but this will factor to
(x + 40(x - 30) = 0
The positive solution is what we want here
x = 30 students in the original group
Check this by finding the cost per student for each scenario
1500/30 = $50.00; original cost
1500/40 = $37.50; actual cost
---------------------
saving: $12.50</span>
6 with the remainer of 4.
<u>Complete Question</u>
The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.
Answer:
0.9875
Step-by-step explanation:
Total Number of Guests, n(S)=80
Let the Event (a friend of the bride) =B
Let the Event (a friend of the groom) =G
n(B) =59
n(G)=50
Therefore:
Number of Guests who was a friend of the bride OR of the groom = 79
Therefore:
The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.
