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4 years ago

I need help with this math work

Mathematics

1 answer:

AveGali [126]4 years ago

4 0

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Samuel currently has an account balance of $3439.96. He open the account five years ago with the deposit of $3104.31. If the int

svet-max [94.6K]

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Step-by-step explanation:

$54.67

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3 years ago

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-3/4 x (-10/9) A. 27/40 B. 5/6 C. -27/40 D. -5/6

Alexeev081 [22]

Answer: B

Step-by-step explanation:

1. Multiplying two negatives equals a positive.

2. Reduce the numbers with the GCF, 3.

3. Reduce the numbers with the greatest common factor, 2.

4. Multiply the fractions which would give you: 5/6

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3 years ago

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I need help please?!!!

Sonbull [250]

Answer:

Step-by-step explanation:

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4 years ago

I need help writing the first 5 terms of the sequence!

Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

$a_{1}=1$

$a_{n}=a_{n-1}+3$

General term of the arithmetic sequence.

$a_{n}=a_{n-1}+d$ , where d is the common difference.

d = 3

$a_{n}=a_{n-1}+3$

Put n = 2 in $a_{n}=a_{n-1}+3$ , we get

$a_{2}=a_1+3$

$a_{2}=1+3$

$a_2=4$

Put n = 3 in $a_{n}=a_{n-1}+3$ , we get

$a_{3}=a_2+3$

$a_{3}=4+3$

$a_3=7$

Put n = 4 in $a_{n}=a_{n-1}+3$ , we get

$a_{4}=a_3+3$

$a_{4}=7+3$

$a_4=10$

Put n = 5 in $a_{n}=a_{n-1}+3$ , we get

$a_{5}=a_4+3$

$a_{5}=10+3$

$a_5=13$

The first five terms of the sequence are 1, 4, 7, 10, 13.

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4 years ago

Steve and Abby purchased a set of vases to place on a 12 foot long mantel above their fireplace. They want to place one vase 1/4

Nonamiya [84]

Answer: One vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

Step-by-step explanation:

You know that lenght of the mantel above their fireplace is 12 feet.

They want to place one vase $\frac{1}{4}$ of the distance from one end of the mantel. This distance in feet is:

$distance_{vase1}=(12feet)(\frac{1}{4})\\\\distance_{vase1}=3feet$

They want to place the other vase $\frac{3}{4}$ of the distance from the same end of the mantel. Therefore, this distance in feet is:

$distance_{vase2}=(12feet)(\frac{3}{4})\\\\distance_{vase2}=\frac{36feet}{4}\\\\distance_{vase2}=9feet$

Therefore, one vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

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3 years ago