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True [87]
3 years ago
13

Help! Question and choices in the picture.​

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

Answer:

I beleive it is A or C. But for me I'd choose C

Step-by-step explanation:

I hope this is right.

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When x=1/2, what is the value of 8x-3 over x?
Taya2010 [7]

\frac{8( \frac{1}{2}) - 3 } { \frac{1}{2} }
\frac{(8 \times \frac{1}{2}) - 3 }{ \frac{1}{2} }  =  \frac{4 - 3}{ \frac{1}{2} }
Because half of 8 is 4

\frac{1}{ \frac{1}{2} }  =  \frac{1 \times 2}{1 \times 1} = 2
Divide 1 by 1/2 or .5... 1 becomes 1/1 and 1/2 is flipped to 2/1, then multiply
5 0
3 years ago
Please please please please please please please please please please please please please answer
Mademuasel [1]
The answer is A. You can check by plugging in the numbers for x.
8 0
3 years ago
Read 2 more answers
Show the region which satisfies simultaneously the inequalities 2x+3y≤8, x-2y≥-3, x≥0, y≥0
Verizon [17]
The first thing you should do is graph the following lines
 2x + 3y = 8
 x-2y = -3
 x = 0
 y = 0
 After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
 2x + 3y≤8, x-2y≥-3, x≥0, y≥0
 The resulting region is the region "R" shown in the attached graph.

8 0
3 years ago
Which of the following could be a function with zeros of —3 and 2? А f(x) = (x - 3)(x + 2) B f(x) = (x = 3)(x - 2) © f(x) = (x+3
Zinaida [17]

Answer:

C

Step-by-step explanation:

to find the zeros you look at what value you would fill in for x to make zero, so (x+3) would have a zero of -3 and (x-2) would have a zero of 2

6 0
3 years ago
The end points of one diagonal of a rhombus are (-5,2) and (1,6). If the coordinates of the 3rd vertexare (-6,10), what are the
ad-work [718]
Look at the picture.

E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)

\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]

D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}

8 0
3 years ago
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