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lianna [129]
3 years ago
6

Express the sum in simplest form. [1/x] + [1/y]

Mathematics
2 answers:
Talja [164]3 years ago
6 0
X/y - y/x 
<span>---------------- </span>
<span>1/y + 1/x </span>

<span>x ² - y ² </span>
<span>----------- </span>
<span>x + y </span>

<span>( x - y ) ( x + y </span>
<span>-------------------- </span>
<span>x + y </span>

<span>x - y hope this helpd</span>
ra1l [238]3 years ago
3 0
It is x-y hope that helps good luck
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Nataly [62]
Multiply 3 by 265 and you have your answer 768
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3 years ago
The diagram shows how cos θ, sin θ, and tan θ relate to the unit circle. Copy the diagram and show how sec θ, csc θ, and cot θ r
DIA [1.3K]
<span>Copy the diagram and show how sec θ, csc θ, and cot θ relate to the unit circle. 

The representation of the diagram is shown if Figure 1. There's a relationship between </span>sec θ, csc θ, and cot θ related the unit circle. Lines green, blue and pink show the relationship. 

a.1 First, find in the diagram a segment whose length is sec θ. 

The segment whose length is sec θ is shown in Figure 2, this length is the segment \overline{OF}, that is, the line in green.

a.2 <span>Explain why its length is sec θ.

We know these relationships:

(1) sin \theta=\frac{\overline{BD}}{\overline{OB}}=\frac{\overline{BD}}{r}=\frac{\overline{BD}}{1}=\overline{BD}

(2) </span>cos \theta=\frac{\overline{OD}}{\overline{OB}}=\frac{\overline{OD}}{r}=\frac{\overline{OD}}{1}=\overline{OD}
<span>
(3) </span>tan \theta=\frac{\overline{FD}}{\overline{OC}}=\frac{\overline{FC}}{r}=\frac{\overline{FC}}{1}=\overline{FC}
<span>
Triangles </span>ΔOFC and ΔOBD are similar, so it is true that:

\frac{\overline{FC}}{\overline{OF}}= \frac{\overline{BD}}{\overline{OB}}<span>

</span>∴ \overline{OF}= \frac{\overline{FC}}{\overline{BD}}= \frac{tan \theta}{sin \theta}= \frac{1}{cos \theta} \rightarrow \boxed{sec \theta= \frac{1}{cos \theta}}<span>

b.1 </span>Next, find cot θ

The segment whose length is cot θ is shown in Figure 3, this length is the segment \overline{AR}, that is, the line in pink.

b.2 <span>Use the representation of tangent as a clue for what to show for cotangent. 
</span>
It's true that:

\frac{\overline{OS}}{\overline{OC}}= \frac{\overline{SR}}{\overline{FC}}

But:

\overline{SR}=\overline{OA}
\overline{OS}=\overline{AR}

Then:

\overline{AR}= \frac{1}{\overline{FC}}= \frac{1}{tan\theta} \rightarrow \boxed{cot \theta= \frac{1}{tan \theta}}

b.3  Justify your claim for cot θ.

As shown in Figure 3, θ is an internal angle and ∠A = 90°, therefore ΔOAR is a right angle, so it is true that:

cot \theta= \frac{\overline{AR}}{\overline{OA}}=\frac{\overline{AR}}{r}=\frac{\overline{AR}}{1} \rightarrow \boxed{cot \theta=\overline{AR}}

c. find csc θ in your diagram.

The segment whose length is csc θ is shown in Figure 4, this length is the segment \overline{OR}, that is, the line in green.

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tensa zangetsu [6.8K]
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Answer:

The numbers will be "11 and 12".

i believe

Step-by-step explanation:

x(x + 1) > x + x + 1 + 109     where x and x+1 are the 2 numbers.

x^2 + x > 2x + 110

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Which of the following options have the same value as 5\%5%5, percent of 353535?
professor190 [17]

Answer:

\frac{5}{100}\times35

0.05\times35

Step-by-step explanation:

<u><em>Given:</em></u>

Which of the following options have the same value as 5% 35, percent of 35?

<u><em>Following Options:</em></u>

5 \times 35

\frac{5}{100}\times35

0.5\times0.35

0.05\times35

\frac{5}{10}\times35

<u><em>Solve:</em></u>

5 % = 0.05=\frac{5}{100}

Thus the following options:

5 \times 35           [ False x ]

5 does not equal 5%

\frac{5}{100}\times35         [True √ ]

5% =\frac{5}{100}

0.5\times0.35      [ False x ]

0.5 = 0.50

0.05\times35       [True √ ]

5% = 0.05=\frac{5}{100}

\frac{5}{10}\times35          [ False x ]

\frac{5}{10}=0.50

Therefore, the options [B] \frac{5}{100}\times35 and [D] 0.05\times35 is True.

<em>Kavinsky</em>

3 0
1 year ago
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