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QveST [7]
3 years ago
15

2. Determine each value of x that solves the following exponential equations given below.

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0
A)5x = 122+3
5x = 125
x = 125/5
x = 25
B) 3x = 81-3
3x = 78
x = 78/3
x = 26
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What is 7.3 = y + 2.8​
zloy xaker [14]

Answer:

4.5

Step-by-step explanation:

7.3= y + 2.8

Subtract 2.8 from both sides

7.3 = y+ 2.8

-2.8     -2.8

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y = 4.5

4 0
3 years ago
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No work needed, just need answer please.
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Answer:

1 is 27.8%

2 is 41.7%

Step-by-step explanation:

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To calculate 2 there is a 15/36 chance (2, 3, 5, 7, 11 are prime)

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Which expression is equivalent to 3(x - 1) – 5(x + 2) ?
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3 years ago
If the sales tax rate is 7.6%, how much sales tax will you pay on a $330 item?
stira [4]

Answer:

If the sales tax rate is 7.6%, how much sales tax will you pay on a $330 item?

Step-by-step explanation:

If the sales tax rate is 7.6%, how much sales tax will you pay on a $330 item?

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Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ
MrRissso [65]

Answer:

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

Step-by-step explanation:

We get the limits of integration:

R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq  4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace

We use the spherical coordinates and  we calculate a triple integral:

V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4  \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}}  \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\

we get:

V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

4 0
3 years ago
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