All categories

3 years ago

In meters what is the value of x? Pls i really dont know how to do this

Mathematics

1 answer:

Hitman42 [59]3 years ago

6 0

Answer:

x = 75 m

Step-by-step explanation:

This is a problem of similar triangles solved using proportions.

In similar triangles, corresponding side lengths are proportional.

Here the small and large triangles are similar because the have all three angles congruent.

By proportions, identifying corresponding sides,

x/45 = 50/30

solve for x

x = 45*(50/30) = 75 m

You might be interested in

Upper bound and lower bound of 17

Licemer1 [7]

Answer:

Step-by-step explanation:

Hey there this si the upper and lower bound for 17

16.5<17<17.5

8 0

2 years ago

You roll a six sided die what is the probability of rolling a 4 or an odd number

12345 [234]

Answer:

we need an out of sorry -_-

5 0

3 years ago

Read 2 more answers

If x > 1, then which of the following has the LEAST value?

jasenka [17]

What are the answers?

5 0

2 years ago

Which is equivalent to 2564 3/4^<br> Help

Yuliya22 [10]

The answer is 64, happy to help!

4 0

2 years ago

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

3 years ago