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3 years ago

9

Help ASAP I don’t get it

1 answer:

GarryVolchara [31]3 years ago

3 0

9514 1404 393

Answer:

positive
negative

Step-by-step explanation:

The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.

That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.

If k is subtracted, instead of added, then the point will be moved downward.

The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.

_____

<em>Comment on the question</em>

The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.

If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.

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Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes

azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

The centre of the ellipse is at the origin and the X axis is the major axis

It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

$\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

Given that the ellipse passes through the point (-3, 1)

Hence,

$\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1$

Cross multiplying we get,

9b² + a² = 1 ²× a²b²
a²b² = 9b² + a²

Multiply by 4 on both sides,

4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

$\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1$

Cross multiply,

4b² + 4a² = 1 × a²b²
a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

3a²b² = 32b²
3a² = 32
a² = 32/3----(3)

Substituting in 2,

32/3 × b² = 4b² + 4 × 32/3
32/3 b² = 4b² + 128/3
32/3 b² = (12b² + 128)/3
32b² = 12b² + 128
20b² = 128
b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

$\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1$

$\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1$

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>

8 0

3 years ago

DF bisects EDG Find FG. The diagram is not to scale.<br><br>A.15<br>B.14<br>C.19<br>D. 28

Ahat [919]

Answer:

○ b. $14$

Step-by-step explanation:

Since <em>DF</em><em> </em>is a segment bisector, set both expressions equal to each other:

3n - 4 = n + 8

-3n - 3n

__________

−4 = −2n + 8

-8 - 8

_________

−12 = −2n

__ ___

−2 −2

$6 = n$ [Plug this back into both expressions above to get the value of 14]; $14 = FG; 14 = EF$

I am joyous to assist you anytime.

6 0

3 years ago

Its #4 help please <br> question 4

sasho [114]

Answer:

I think s(2s) = 205

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Explain how to change 86% into an equivalent ratio written in simplest form

stepan [7]

Answer:

I can't explain here since I can't write numbers.

Step-by-step explanation:

7 0

2 years ago

Find L when P= 24 and W = 6.<br> P = 2L+ 2W (perimeter of a rectangle)<br> L =

Anon25 [30]

Answer:

6

Step-by-step explanation:

24 = 2L + 2(6), multiply...

24 = 2L + 12, subtract 12 to both sides...

12 = 2L, divide 2 to both sides to isolate the varibale L

6 = L

Therefroe, L = 6

8 0

2 years ago