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Paladinen [302]
4 years ago
14

Two commonly used sulfonic acids are methanesulfonic acid (CH3SO3H) and trifluoromethanesulfonic acid (CF3SO3H). Which acid's co

njugate base is the better leaving group?
Chemistry
1 answer:
cluponka [151]4 years ago
4 0

Answer:trifluoromethanesulfonic acid (CF3SO3H).

Explanation:

The trifluoromethanesulfonic acid (CF3SO3H) has a halogen atom which stabilizes the leaving group by withdrawal of charge from the SO3- moiety. The methanesulfonic acid (CH3SO3H) contains an electron pushing group which tends to destabilize the charge centre. The better leaving group will be the stabilized anion which in this case is trifluoromethanesulfonic acid (CF3SO3H). This typifies the role of stabilizing factors in formation of chemical species.

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solmaris [256]

The mass of the solute required is 250.25 g.

<h3>What is the mass of the solute?</h3>

We know that the number of moles of the solute can be used to obtain the mass of the solute that is  required. We can now try to find the mass of the solute that is required.

Concentration of the solution = 0.350M

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Number of moles of the solute = 0.350M *  6.5 L

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We now have the mass of the solute as;

2.275 moles  * 110 g/mol

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Th measured mass of the solute that we would have to use is 250.25 g.

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A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?

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