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Karolina [17]
3 years ago
8

What is the relationship in numbers of particles and pressure

Chemistry
1 answer:
Alina [70]3 years ago
3 0
Key Concepts and Summary
The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law). Under the same conditions of temperature and pressure, equal volumes of all gases contain the same number of molecules (Avogadro's law).
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What is the balance of NH3+HCL=NH4CL+H2O
Karolina [17]

Answer:

Hydrogen chloride react with ammonium hydroxide

HCl + NH3•H2O → NH4Cl + H2O

Explanation:

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How would the equilibrium change if NO2 were added to SO2(g) + NO2(g) NO(g) + SO3(g) + heat?
ahrayia [7]
The answer to this question would be that the amount of No and SO3 would increase. The correct choice is C. 
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3 years ago
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When a chemist collects hydrogen gas over water, she ends up with a mixture of hydrogen and water vapor in her collecting bottle
elixir [45]

<u>Answer:</u> The partial pressure of hydrogen is 93.9 kPa.

<u>Explanation:</u>

To calculate the partial pressure of hydrogen, we will follow Dalton's Law.

This law states that the total pressure of a mixture of gases is equal to the sum of the individual pressures exerted by the constituent gases.

Mathematically,

p_{total}=p_A+p_B

According to the question,

p_{total}=p_{H_2O}+p_{H_2}

We are given:

p_{total}=97.1 kPa

p_{H_2O}=3.2kPa

p_{H_2}= ?kPa

Putting values in above equation, we get:

97.1kPa=3.2kPa+p_{H_2}

p_{H_2}= 93.9kPa

Hence, the partial pressure of hydrogen is 93.9 kPa.

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2 years ago
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What is the molecular weight of bromoform if 2.50X10^-2 mol weighs 6.33 g
babymother [125]
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8 0
3 years ago
Calculate the molarity of an hcl solution if a 10.00 ml sample requires 25.24 ml of a 1.600 m naoh solution to be neutralized.
AlladinOne [14]

Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

<u>Step 1:</u> Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

<u>Step 2:</u> The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

C1 * 0.01 = 1.6 * 0.02524

C1 = (1.6*0.02524)/0.01

C1 = 4.04M

The molarity of the HCl solution should be 4.04 M

6 0
3 years ago
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